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# f(x)? watch

1. I've noticed equations in both my normal maths (edexcel, non-calculator tomorrow) and my further maths (aqa) past papers and revision with f(x) in somewhere and even though we've gone over it several times in the lessons I don't understand it or remember how to solve it. Could someone explain ot to me please?
I'll include a picture of the question I got stuck on today, ignore my wrong answers.
2. (Original post by IfYouCanDreamIt)
I've noticed equations in both my normal maths (edexcel, non-calculator tomorrow) and my further maths (aqa) past papers and revision with f(x) in somewhere and even though we've gone over it several times in the lessons I don't understand it or remember how to solve it. Could someone explain ot to me please?
I'll include a picture of the question I got stuck on today, ignore my wrong answers.
The second question answer is 2

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3. (Original post by IfYouCanDreamIt)
I've noticed equations in both my normal maths (edexcel, non-calculator tomorrow) and my further maths (aqa) past papers and revision with f(x) in somewhere and even though we've gone over it several times in the lessons I don't understand it or remember how to solve it. Could someone explain ot to me please?
I'll include a picture of the question I got stuck on today, ignore my wrong answers.
You basically divide where it meets the x values which is -4 divide by 4 Which is -1, then the next x value is 4 so you divide it by 4 which is 1 then the difference between then is 2

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4. (Original post by IfYouCanDreamIt)
I've noticed equations in both my normal maths (edexcel, non-calculator tomorrow) and my further maths (aqa) past papers and revision with f(x) in somewhere and even though we've gone over it several times in the lessons I don't understand it or remember how to solve it. Could someone explain ot to me please?
I'll include a picture of the question I got stuck on today, ignore my wrong answers.
f(ax) --> squashes graph parallel to the x axis by scale factor 1/a
so both of the points that cross the x axis are multiplied by 1/4 (eg the point which crosses the x axis at (4,0) will become (1,0))
then work out the distance between the 2 new points
5. (Original post by Monsor)
You basically divide where it meets the x values which is -4 divide by 4 Which is -1, then the next x value is 4 so you divide it by 4 which is 1 then the difference between then is 2

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(Original post by surina16)
f(ax) --> squashes graph parallel to the x axis by scale factor 1/a
so both of the points that cross the x axis are multiplied by 1/4 (eg the point which crosses the x axis at (4,0) will become (1,0))
then work out the distance between the 2 new points
Thankyou, I've realised that I meant to write (0,1) for the first one rather than (1,0), I just had a blonde moment.
The second question makes sense now, I undestand where I went wrong, I multiplied each of the points by four rather than dividing, so thankyou
6. (Original post by IfYouCanDreamIt)
Thankyou, I've realised that I meant to write (0,1) for the first one rather than (1,0), I just had a blonde moment.
The second question makes sense now, I undestand where I went wrong, I multiplied each of the points by four rather than dividing, so thankyou
no problem, good luck in tomorrow's exam! hoping the exam doesn't contain any 'controversial' questions...
7. (Original post by IfYouCanDreamIt)
Thankyou, I've realised that I meant to write (0,1) for the first one rather than (1,0), I just had a blonde moment.
The second question makes sense now, I undestand where I went wrong, I multiplied each of the points by four rather than dividing, so thankyou
You're welcome, best of luck tomorrow aim for that a*

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