Ionic Equations for Concentrated sulfuric acid and Potassium Chloride Watch

LorryBalls
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Simplest Ionic Equations for Concentrated sulfuric acid and Potassium Chloride?
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LorryBalls
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pineneedles
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H2SO4 + 2KCl > K2SO4 + 2HCl is the simplest it will go.
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LorryBalls
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(Original post by pineneedles)
H2SO4 + 2KCl > K2SO4 + 2HCl is the simplest it will go.
The mark scheme says. Is there any explanation for these ones?

M1 H2SO4 + 2Cl → 2HCl + SO42–
OR H2SO4 + Cl → HCl + HSO4–
OR H++ Cl → HCl
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pineneedles
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(Original post by LorryBalls)
The mark scheme says. Is there any explanation for these ones?

M1 H2SO4 + 2Cl → 2HCl + SO42–
OR H2SO4 + Cl → HCl + HSO4–
OR H++ Cl → HCl
I may have been wrong hahah. I think that I didn't take into account the states of the reactants. Normally in writing an ionic equation you would look at the species which haven't changed oxidation states, but nothing in that equation has appeared to change oxidation state. Were you given any physical states in the question?
I apologise for potentially confusing you further 😊

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Jpw1097
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(Original post by LorryBalls)
The mark scheme says. Is there any explanation for these ones?

M1 H2SO4 + 2Cl → 2HCl + SO42–
OR H2SO4 + Cl → HCl + HSO4–
OR H++ Cl → HCl
HCl reacts with H2SO4 to form KHSO4 and HCl. Chloride ions are not strong enough reducing agents to reduce H2SO4 as chloride ions are quite small and so the outer electrons are held strongly by the nucleus. Therefore the reaction does not proceed any further.

However, the KBr will react with H2SO4 to form KHSO4 and HBr. Bromide ions are strong enough reducing agents to reduce H2SO4 to SO2. Iodide ions can reduce H2SO4 further still to sulphur and even as far as hydrogen sulphide (H2S).
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