AQA AS 2016 - CHEM1 (Resit) Unoffical Mark Scheme Watch

SirRaza97
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EDIT: Thanks to everyone who has helped in this thread. If anyone can remember the marks for each question I will add them in for you guys! Also the Bold stuff after some thought are probably the correct answers or something along the lines of it. Good luck to everyone in the rest of their exams

EDIT 2: I've added in marks from what I can remember

Here is my unofficial mark scheme. Anything in bold I am not sure if it's right. So if you have any idea then please tell me so i can add it! If i have missed anything out then aslo let me know!

Section A

1.
a) Relative Atomic mass Definition (2)
b) Magnetic Field (1)
c) - Ions accept electrons -Current is formed which is proportional to abundance (2)
d) Something like 28.065 for the RAM (3)
e) Similarity= Peaks still at original m/z values becuase +1 ions are still formed/
same relative abundance (or same height of peaks) because same sample is used so similar amount of the isotopes are present
-Difference - Peaks at half the m/z values becasue high energy electrons will produce +2 ions (4)

2. (Can't rmember what topic this was. I think it was about Van Der Waals)
a) -Electron Density randomly shifts -Creating areas of +ve and -ve charge on molecule - Attraction between molecules which is intermolecular force/VDW (3)
b) O-H bond big electronegative difference allows for hydrogen bonds. Hydrogen bonds are stronger than VDW. (3)
c) Fractional Distiallation/Heat under reflux will sperate these (1)
d) The Se molecule is larger. This means the VDW forces are stronger between molecules (2)

3. (Questions about Alkanes?)
a) Group is alkane (1)
b) 2,2,4 - trimethylpentane (might accept 2,4,4 - trimethylpentane) (1)
c) C8H18 + 12.5O2 ------> 9H2O + 8CO2 (2)
d) but-1-ene (1)
e) C14H30 (1)
f) Thermal Cracking. High temp and high pressure (2)
g) Isomers question. Chain isomer = H2C=C(CH3)2 Postion isomer = But-2-ene Functional Isomer = Cyclic Alkane so cyclicbutane (4)

4. (The weird reactions and the shapes question?)
a) Balancing equation I couldn't remember (2)
b) Cu2(OH)2CO3 + 4HCl -----> 2CuCl2 + 3H2O + CO2 (2)
c) Effervescense(1)
d) Cu3O8H2C2 or in the structural form Cu3(CO3)2(OH)2 (3)
e) Shapes question - SF6 = Octohedral , 90 degrees -SF4 = See-Saw shape. Lone pair on the horizontal plane. Angles 90, 120 or 180 degrees. Probably will accept -2.5 degrees off each angle. (6)

Section B

5. (Period 3 stuff)
a) - Ionisation energies increase -Increasing proton number - Similar Shielding -Attraction between outer electron and nuclues gets stronger -The bigger nuclear charge reduces atomic radius (I don't think this point is needed) (4)
b) -Silicon has highest melting point. -Because of macromolecular/Giant covelant structure. -Strong covelant bonds throughout structure. -Requires high amounts of energy to break. (3)
c) The 2 elements that you could've choosed from were Aluminuim because removing electron from 3p shell or Sulphur because of pair repulsion in 3p shell. (2/3)
d) -Element Y is Sulphur. -Large jump in eneries from 6th to 7th ionisation enegies -So 7th electron in inner shell so sulphur must be the element Y. (3)

6. (Calculations)
a) 0.113m3 (3 sig figs needed) (3/4)
b) 1065 Kg or 1.065x106 g (2/3)
c) Percentage yield = 49.3% (4/5)
d) Method 1 because its 100% atom economy. Only producing one product. (1)
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MotorboatMyGoat
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(Original post by SirRaza97)
Here is my unofficial mark scheme. Anything in bold I am not sure if it's right. So if you have any idea then please tell me so i can add it! If i have missed anything out then aslo let me know!

Section A

1.
a) Relative Atomic mass Definition
b) Magnetic Field
c) - Ions accept electrons -Current is formed which is proportional to abundance
d) Something like 28.065 for the RAM
e) Similarity= Peaks still at original m/z values becuase +1 ions are still formed. Difference - Peaks at half the m/z values becasue high energy electrons will produce +2 ions

2. (Can't rmember what topic this was. I think it was about Van Der Waals)
a) -Electron Density randomly shifts -Creating areas of +ve and -ve charge on molecule - Attraction between molecules which is intermolecular force/VDW
b) O-H bond big electronegative difference allows for hydrogen bonds. Hydrogen bonds are stronger than VDW.
c) The Se molecule is larger? This means the VDW forces are stronger between molecules

3. (Questions about Alkanes?)
a) Group is alkane
b) 2,4,4 - trimethylpentane or equivalent
c) C8H18 + 12.5O2 ------> 9H2O + 8CO2
d) but-1-ene
e) C14H30
f) Isomers question. Chain isomer = H2C=C(CH3)2 Postion isomer = But-2-ene Functional Isomer = Cyclic Alkane so basically a square skeltal formula

4. (The weird reactions and the shapes question?)
a) Balancing equation I couldn't remember
b) Cu2(OH)2CO3 + 4HCl -----> 2CuCl2 + 3H2O + CO2
c) Effervescense
d) Something like Cu3O8H2C2
e) Shapes question - SF6 = Octohedral , 90 degrees SF4 = I thought it was trigonal bipyramidal with the lone pair in the horzontal plane with angles of 120 degrees and 90 degrees but others saying it was tetrahedral with and of 107 degress

Section B

5. (Period 3 stuff)
a) - Ionisation energies increase -Increasing proton number - Similar Shielding -Attraction between outer electron and nuclues gets stronger -The bigger nuclear charge reduces atomic radius (I don't think this point is needed)
b) -Silicon has highest melting point. -Because of macromolecular/Giant covelant structure. -Strong covelant bonds throughout structure. -Requires high amounts of energy to break.
c) -Element Y is Sulphur. -Large jump in eneries from 6th to 7th ionisation enegies -So 7th electron in inner shell so sulphur must be the element Y.

6. (Calculations)
a) 0.113m3 (3 sig figs needed)
b) 1065 Kg or 1.065x106 g
c) Percentage yield = 49.3%
d) Method 1 because its 100% atom economy. Only producing one product.
I think I agree with all, but 3b will only accept 2,2,4-trimethylpentane, and 4e was a sea saw shape so will accept angles 90,120 and 180
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SirRaza97
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(Original post by MotorboatMyGoat)
I think I agree with all, but 3b will only accept 2,2,4-trimethylpentane, and 4e was a sea saw shape so will accept angles 90,120 and 180
But you can read it backwards? So why not 2,4,4? It's the same thing right?
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Super199
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(Original post by SirRaza97)
But you can read it backwards? So why not 2,4,4? It's the same thing right?
I think you do it so numbers are as low as possible
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MotorboatMyGoat
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(Original post by SirRaza97)
But you can read it backwards? So why not 2,4,4? It's the same thing right?
No I'm pretty sure you have to write smallest numbers as possible. May say accept 2,4,4
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Sniperdon227
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how do vdW form can someone write an actual ms answer please googles a load of bull
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SirRaza97
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(Original post by MotorboatMyGoat)
No I'm pretty sure you have to write smallest numbers as possible. May say accept 2,4,4
(Original post by Super199)
I think you do it so numbers are as low as possible
Okay I guess so. I'll add it in

(Original post by Sniperdon227)
how do vdW form can someone write an actual ms answer please googles a load of bull
My answer seems pretty plausible. This is the best Mark scheme ur gonna get for now.
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Charco63
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(Original post by SirRaza97)
Here is my unofficial mark scheme. Anything in bold I am not sure if it's right. So if you have any idea then please tell me so i can add it! If i have missed anything out then aslo let me know!

Section A

1.
a) Relative Atomic mass Definition
b) Magnetic Field
c) - Ions accept electrons -Current is formed which is proportional to abundance
d) Something like 28.065 for the RAM
e) Similarity= Peaks still at original m/z values becuase +1 ions are still formed. Difference - Peaks at half the m/z values becasue high energy electrons will produce +2 ions

2. (Can't rmember what topic this was. I think it was about Van Der Waals)
a) -Electron Density randomly shifts -Creating areas of +ve and -ve charge on molecule - Attraction between molecules which is intermolecular force/VDW
b) O-H bond big electronegative difference allows for hydrogen bonds. Hydrogen bonds are stronger than VDW.
c) The Se molecule is larger? This means the VDW forces are stronger between molecules

3. (Questions about Alkanes?)
a) Group is alkane
b) 2,2,4 - trimethylpentane (might accept 2,4,4 - trimethylpentane)
c) C8H18 + 12.5O2 ------> 9H2O + 8CO2
d) but-1-ene
e) C14H30
f) Isomers question. Chain isomer = H2C=C(CH3)2 Postion isomer = But-2-ene Functional Isomer = Cyclic Alkane so basically a square skeltal formula

4. (The weird reactions and the shapes question?)
a) Balancing equation I couldn't remember
b) Cu2(OH)2CO3 + 4HCl -----> 2CuCl2 + 3H2O + CO2
c) Effervescense
d) Something like Cu3O8H2C2
e) Shapes question - SF6 = Octohedral , 90 degrees SF4 = I thought it was trigonal bipyramidal with the lone pair in the horzontal plane with angles of 120 degrees and 90 degrees but others saying it was tetrahedral with and of 107 degress

Section B

5. (Period 3 stuff)
a) - Ionisation energies increase -Increasing proton number - Similar Shielding -Attraction between outer electron and nuclues gets stronger -The bigger nuclear charge reduces atomic radius (I don't think this point is needed)
b) -Silicon has highest melting point. -Because of macromolecular/Giant covelant structure. -Strong covelant bonds throughout structure. -Requires high amounts of energy to break.
c) The elements that you could say were Aluminuim because removing electron form 3p shell and Sulfur because of pair repulsion.
d) -Element Y is Sulphur. -Large jump in eneries from 6th to 7th ionisation enegies -So 7th electron in inner shell so sulphur must be the element Y.

6. (Calculations)
a) 0.113m3 (3 sig figs needed)
b) 1065 Kg or 1.065x106 g
c) Percentage yield = 49.3%
d) Method 1 because its 100% atom economy. Only producing one product.
Could yoU explain how you got 0.113 instead of 0.451/0.453
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MotorboatMyGoat
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(Original post by Sniperdon227)
how do vdW form can someone write an actual ms answer please googles a load of bull
I put non-polar molecules, have very little difference in electronegativity so VDW forces form between molecules.
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SirRaza97
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(Original post by Charco63)
Could yoU explain how you got 0.113 instead of 0.451/0.453
The ration was 1:1 for phsophorus to the oxide. So work out the mol of the phsphorus = 220g/124 = 1.774 mol

Then use pV = nRT to find volume. 500 degress celcius (converted to 773K) and 101kPa

V = (1.774 x 8.31 x 773)/101000 = 0.1128 m3 = 0.113 m3
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Engineerrookie
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(Original post by SirRaza97)
Here is my unofficial mark scheme. Anything in bold I am not sure if it's right. So if you have any idea then please tell me so i can add it! If i have missed anything out then aslo let me know!

Section A

1.
a) Relative Atomic mass Definition
b) Magnetic Field
c) - Ions accept electrons -Current is formed which is proportional to abundance
d) Something like 28.065 for the RAM
e) Similarity= Peaks still at original m/z values becuase +1 ions are still formed. Difference - Peaks at half the m/z values becasue high energy electrons will produce +2 ions

2. (Can't rmember what topic this was. I think it was about Van Der Waals)
a) -Electron Density randomly shifts -Creating areas of +ve and -ve charge on molecule - Attraction between molecules which is intermolecular force/VDW
b) O-H bond big electronegative difference allows for hydrogen bonds. Hydrogen bonds are stronger than VDW.
c) The Se molecule is larger? This means the VDW forces are stronger between molecules

3. (Questions about Alkanes?)
a) Group is alkane
b) 2,2,4 - trimethylpentane (might accept 2,4,4 - trimethylpentane)
c) C8H18 + 12.5O2 ------> 9H2O + 8CO2
d) but-1-ene
e) C14H30
f) Isomers question. Chain isomer = H2C=C(CH3)2 Postion isomer = But-2-ene Functional Isomer = Cyclic Alkane so basically a square skeltal formula

4. (The weird reactions and the shapes question?)
a) Balancing equation I couldn't remember
b) Cu2(OH)2CO3 + 4HCl -----> 2CuCl2 + 3H2O + CO2
c) Effervescense
d) Something like Cu3O8H2C2
e) Shapes question - SF6 = Octohedral , 90 degrees SF4 = I thought it was trigonal bipyramidal with the lone pair in the horzontal plane with angles of 120 degrees and 90 degrees but others saying it was tetrahedral with and of 107 degress

Section B

5. (Period 3 stuff)
a) - Ionisation energies increase -Increasing proton number - Similar Shielding -Attraction between outer electron and nuclues gets stronger -The bigger nuclear charge reduces atomic radius (I don't think this point is needed)
b) -Silicon has highest melting point. -Because of macromolecular/Giant covelant structure. -Strong covelant bonds throughout structure. -Requires high amounts of energy to break.
c) The elements that you could say were Aluminuim because removing electron form 3p shell and Sulfur because of pair repulsion.
d) -Element Y is Sulphur. -Large jump in eneries from 6th to 7th ionisation enegies -So 7th electron in inner shell so sulphur must be the element Y.

6. (Calculations)
a) 0.113m3 (3 sig figs needed)
b) 1065 Kg or 1.065x106 g
c) Percentage yield = 49.3%
d) Method 1 because its 100% atom economy. Only producing one product.
Not sure if you would get marks for the skeletal as it asked for displayed formula
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thenextchemist
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(Original post by Charco63)
Could yoU explain how you got 0.113 instead of 0.451/0.453
Yes please
I want to know this too
I'm so sure the answer is 0.451


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Louisss
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thanks man! do you remember how many marks each question was worth?
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thenextchemist
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(Original post by SirRaza97)
The ration was 1:1 for phsophorus to the oxide. So work out the mol of the phsphorus = 220g/124 = 1.774 mol

Then use pV = nRT to find volume. 500 degress celcius (converted to 773K) and 101kPa

V = (1.774 x 8.31 x 773)/101000 = 0.1128 m3 = 0.113 m3
Wasn't is P4O10 - for the mr?
You just did 124 for the Mr


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Sniperdon227
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(Original post by MotorboatMyGoat)
I put non-polar molecules, have very little difference in electronegativity so VDW forces form between molecules.
that's what i put my g, i think you have to talk about electron clouds and how at any given time one side is less neg and one side is more neg so attract other electron clouds etc...
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SirRaza97
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(Original post by Engineerrookie)
Not sure if you would get marks for the skeletal as it asked for displayed formula
I put the displayed dont worry. Past mark schemes allowed it so it might.
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SirRaza97
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(Original post by Bloom77)
Wasn't is P4O10 - for the mr?
You just did 124 for the Mr


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we new how much mass of P4 which was 220g. We worked the mol of that? Maybe I misread the question?
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SirRaza97
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(Original post by Sniperdon227)
that's what i put my g, i think you have to talk about electron clouds and how at any given time one side is less neg and one side is more neg so attract other electron clouds etc...
That's what I thought they would ask for. It was a worth a few marks.
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SirRaza97
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(Original post by Louisss)
thanks man! do you remember how many marks each question was worth?
No sorry man
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j5994
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for the balancing equation questions, if you got the other products right but they aren't balanced, do you get 1/2?
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