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    A particle P of weight W newtons is attached to one end of a light inextensible string. The other end of the string is attached to a fixed point O. A horizontal force of magnitude 5N is applied to P. The particle P is in equilibrium with the string taut and with OP making an angle of 25° to the downward vertical.

    Edit: Find the tension in the string
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    (Original post by Steelmeat)
    A particle P of weight W newtons is attached to one end of a light inextensible string. The other end of the string is attached to a fixed point O. A horizontal force of magnitude 5N is applied to P. The particle P is in equilibrium with the string taut and with OP making an angle of 25° to the downward vertical.

    Edit: Find the tension in the string
    Well, what have you tried?
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    Have tried drawing a diagram?
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    (Original post by Zacken)
    Well, what have you tried?
    so far from P i've drawn a little line with an arrow which has Mg on the end of it

    (Original post by ravioliyears)
    Have tried drawing a diagram?
    Actually the diagram's on the piece of paper i have but i just couldn't be bothered to take a picture and post it on here...
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    (Original post by Steelmeat)
    so far from P i've drawn a little line with an arrow which has Mg on the end of it



    Actually the diagram's on the piece of paper i have but i just couldn't be bothered to take a picture and post it on here...
    I hope the Mg arrow is vertically downwards. Anyhow, resolve horizontally.
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    (Original post by Zacken)
    I hope the Mg arrow is vertically downwards. Anyhow, resolve vertically and horizontally.
    yup i forgot to mention.

    oh ok


    Edit: I just seem to be getting this and this for horizontal and vertical

    (<----) 5N
    Vertically: Mg
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    (Original post by Steelmeat)
    yup i forgot to mention.

    oh ok


    Edit: I just seem to be getting this and this for horizontal and vertical

    (<----) 5N
    Vertically: Mg
    There are components of tension acting both horizonttally and vertically.
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    (Original post by Zacken)
    There are components of tension acting both horizonttally and vertically.
    I can't seem to see it in the diagram :/
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    (Original post by Steelmeat)
    I can't seem to see it in the diagram :/
    Upload your diagram.

    Tension is an arrow pointing along the string from P to O. It acts at an angle to the downward vertical. Resolve.
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    (Original post by Steelmeat)
    I can't seem to see it in the diagram :/
    Unsure what downward vertical meant but my attempt - Name:  image.jpg
Views: 48
Size:  395.9 KB
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    (Original post by Zacken)
    Upload your diagram.

    Tension is an arrow pointing along the string from P to O. It acts at an angle to the downward vertical. Resolve.
    (Original post by Middriver)
    Unsure what downward vertical meant but my attempt - Name:  image.jpg
Views: 48
Size:  395.9 KB
    ahhhh i see i just didn't label the tension in the string as a letter oops thanks a lot
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    (Original post by Steelmeat)
    ahhhh i see i just didn't label the tension in the string as a letter oops thanks a lot
    No worries, is that what downward vertical meant btw?
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    (Original post by Middriver)
    No worries, is that what downward vertical meant btw?
    yes vertically down is another way of putting it
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    Resolve all the forces in two planes, you will always get a simultaneous or just a simple eq e.g tcos40=5gcos50
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    (Original post by Middriver)
    No worries, is that what downward vertical meant btw?
    From O, draw a line passing through O, vertically downwards. The angle the string makes with this line is the angle with the downward vertical.
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    (Original post by Zacken)
    From O, draw a line passing through O, vertically downwards. The angle the string makes with this line is the angle with the downward vertical.
    Thanks
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    (Original post by Steelmeat)
    ahhhh i see i just didn't label the tension in the string as a letter oops thanks a lot
    (Original post by Middriver)
    Thanks
    No problem.
 
 
 
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