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Edexcel AS Level Maths - Statistics (S1) Exam - 15th June 2016 watch

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    I thought it would be a good idea to have a thread for the S1 exam for Edexcel maths where we can contribute resources, revision tips and ask for help

    Thanks!

    Here are some good resources to start this thread off!

    Revision notes:
    https://0cc6f1255ee36c27d4aeb00893d3...n%20Sheets.pdf

    https://0cc6f1255ee36c27d4aeb00893d3...S1%20Notes.pdf

    http://www.mrbartonmaths.com/resourc...evision/S1.pdf

    http://www.mathsbox.org.uk/revisionn...on%20Notes.pdf


    Useful websites:
    http://www.mrbartonmaths.com/alevel.htm

    https://hegartymaths.com/ (you have to sign up, but it's completely free!)

    http://www.examsolutions.net/maths-r...cification.php
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    There's already an S1 thread
    http://www.thestudentroom.co.uk/show...rimary_content
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    ^^^^ rah


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    In June 2015 1(d) I am getting Q1 as 62! I don't know whats wrong! how do you get 9/15? My working is : 60+(21-15/21-6)*5. How it is possible to get 9 if u subtract 21-15??
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    (Original post by pranto96)
    In June 2015 1(d) I am getting Q1 as 62! I don't know whats wrong! how do you get 9/15? My working is : 60+(21-15/21-6)*5. How it is possible to get 9 if u subtract 21-15??
    You use linear interpolation.
    So you do (15-6/21-6)*5 + 60 = 63
    You just got the numbers on the top of the fraction mixed up
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    Anyone have any ideas on like the hardest question you could get. I dislike stats due to there being so many words. So yeah if you have any ideas please tell me. Thanks
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    How did everyone find it? Not too bad this being my 3rd attempt haha

    1b)Wiggles c)0.994 d)w=0.722+0.0142d e)5.69
    2a)0.5=2p +q b)0.15 c)0.175 d)0.45 f) 0.445 and 0.485
    3a)2.348 b *didn't get this one* c)-133.9 d)-0.754
    4a) 0 b)t=0.03 u=0.22 9/11(0.818) 15/12(0.682) estimate=35
    5a)w=2/3 h=12.75 b) 3.47 c) 3.43,0.680 d) 0.2546
    6a)0.0668 b)206(.something) minutes c)0.36

    I don't expect all of my answers to be correct so please take them with a pinch of salt, appreciate any corrections and explanations
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    (Original post by chewitt77)
    How did everyone find it? Not too bad this being my 3rd attempt haha

    1b)Wiggles c)0.994 d)w=0.722+0.0142d e)5.69
    2a)0.5=2p +q b)0.15 c)0.175 d)0.45 f) 0.445 and 0.485
    3a)2.348 b *didn't get this one* c)-133.9 d)-0.754
    4a) 0 b)t=0.03 u=0.22 9/11(0.818) 15/12(0.682) estimate=35
    5a)w=2/3 h=12.75 b) 3.47 c) 3.43,0.680 d) 0.2546
    6a)0.0668 b)206(.something) minutes c)0.36

    I don't expect all of my answers to be correct so please take them with a pinch of salt, appreciate any corrections and explanations
    2f the probabilities were 0.475 and 0.375 respectively
    my estimate for the number of people was 32.
    the height was 17cm and the width was 0.5cm
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    (Original post by alexesl17)
    2f the probabilities were 0.475 and 0.375 respectively
    my estimate for the number of people was 32.
    the height was 17cm and the width was 0.5cm
    I also got 2f) 0.445 and 0.485 so you may of messed up their bro.
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    (Original post by TighFR)
    I also got 2f) 0.445 and 0.485 so you may of messed up their bro.
    nah i dont mess up
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    (Original post by alexesl17)
    nah i dont mess up
    Loooool, we'll see.
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    (Original post by TighFR)
    Loooool, we'll see.
    walk me through then how you got those answers
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    If you look at the last few years grade boundaries, it is between 59-61 for an A
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    (Original post by alexesl17)
    walk me through then how you got those answers
    I created a probability distribution for Rebecca where I replaced the x values ie 2 for 1/2 as it was R=1/X.Then you just work out all the possible outcomes (you can use a tree diagram but to me that long). The summation of all the possible outcomes was for me 0.445.
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    Any unofficial markschemes out there yet?
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    (Original post by TighFR)
    I created a probability distribution for Rebecca where I replaced the x values ie 2 for 1/2 as it was R=1/X.Then you just work out all the possible outcomes (you can use a tree diagram but to me that long). The summation of all the possible outcomes was for me 0.445.
    yea i got a couple of friends that did that method but the thing is that both girls use the same outcome from the spinner i.e its not one spin for sarah and one spin for rebecca, so the only way sarah can win is if the spinner lands on 3/2 or 2 (because rebecas values of 1/3/2 and 1/2 would be smaller) and the probability that it lands on 3/2 is 0.3 as given in the table and that it lands on 2 is p which is 0.175, hence 0.3+0.175 = 0.475. hope u understand my explanation
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    (Original post by TighFR)
    I created a probability distribution for Rebecca where I replaced the x values ie 2 for 1/2 as it was R=1/X.Then you just work out all the possible outcomes (you can use a tree diagram but to me that long). The summation of all the possible outcomes was for me 0.445.
    To be fair, you are probably right as I originally left this question not knowing how to do it. What did you do?
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    (Original post by TighFR)
    To be fair, you are probably right as I originally left this question not knowing how to do it. What did you do?
    same i just didnt understand it!
    I think ive done okay on the others except the venn Diagram. Edexcel are horrible i hated that question.
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    (Original post by alexesl17)
    nah i dont mess up
    (Original post by TighFR)
    Loooool, we'll see.
    Most people I know said it was 0.475 and 0.375.
    Also why aren't you guys on the S1 thread
    http://www.thestudentroom.co.uk/show....php?t=3932531
 
 
 
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