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    A car starts from rest and moves with constant acceleration along a straight horizontal road. The car reaches a speed of Vms^{-1} in 20 secs. It moves at a constant speed Vms^{-1} for the next 30 secs, then moves with constant deceleration 0.5ms^{-2}. It moves at speed 8ms^{-1} for the next 15 secs and then moves with constant deceleration 1/3ms^{-2} until lit comes to rest.

    Sketch a speed time graph for this journey
    Find
    the value of V
    total time for the journey
    total distance travelled by the car

    I've done the graph and found V
    I got V as 14ms^{-1}

    i've split up the graph after 50s into a trapezium rectangle and triangle in that order

    Edit:actually nvm it's just usiing v=u+at a bunch xD sorry just disregard this thread until i get to part D(distance bit)
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    Answering to bump off the unanswered list.
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    (Original post by Zacken)
    Answering to bump off the unanswered list.
    For the total distance i got 908 Metres is that right?
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    (Original post by Steelmeat)
    For the total distance i got 908 Metres is that right?
    I dunno, post your working.
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    (Original post by Zacken)
    I dunno, post your working.
    oh boy this is gonna be long one
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    (Original post by Zacken)
    I dunno, post your working.
    so we need to do all parts of the question besides sketch the graph to know the answer for the final question

    For V
    v=v u=0 s=140 t=20
    s=\left( \dfrac{v+u}{2}\right)t
    140=10v
    v=14ms^{-1}

    for total time
    the time for the first chunk of the journey we're told is 50secs
    we calculate the time for the last 2 remaining section on the graph
    u=14 v=8 a=-0.5 t=t
    v=u+at
    8=14-0.5t
    0.5t=6
    t=12

    u=8 v=0 a=-\frac{1}{3} t=t
    v=u+at
    0=8-\frac{1}{3}t
    t=24

    50+12+15+24=101 secs

    distance i separated my graph up into shapes
    from left to right
    a triangle: 0.5x20x16= 140
    a rectangle: 14x30=420
    a trapezium: 0.5(14+8)12=132
    a rectangle: 15x8=120
    a thin triangle: 0.5x8x24=96

    140+420+132+120+96=908

    so is it right or did i make a huge mistake somewhere?
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    notnek
    is it right? ^^
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    (Original post by Steelmeat)
    It moves at a constant speed Vms^{-1} for the next 30 secs, then moves with constant deceleration 0.5ms^{-2}. It moves at speed 8ms^{-1} for the next 15 secs...
    This part of your question is confusingly worded. Have you posted the question as it is written?
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    (Original post by notnek)
    This part of your question is confusingly worded. Have you posted the question as it is written?
    let me check that bit again ...

    sorry my bad i missed a bit out
    It moves at constant speed V ms^{-1} for the next 30 seconds, then moves with constant deceleration 0.5ms^{-2} until it has speed 8ms^{-1}.
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    (Original post by Steelmeat)
    let me check that bit again ...

    sorry my bad i missed a bit out
    It moves at constant speed V ms^{-1} for the next 30 seconds, then moves with constant deceleration 0.5ms^{-2} until it has speed 8ms^{-1}.
    Just post the full question as a picture or link.
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    (Original post by Zacken)
    Just post the full question as a picture or link.
    ok
    a picture it is then

    Edit: sorry about that rest your necks with this

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    (Original post by Steelmeat)

    140+420+132+120+96=908

    so is it right or did i make a huge mistake somewhere?
    After numerous neck craning: that's right.
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    (Original post by Zacken)
    After numerous neck craning: that's right.
    haha sorry about that i realised it was upside down and unfortunately you came to early and i hadn't posted the edited version yet sorry about that xD
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    (Original post by Steelmeat)
    haha sorry about that i realised it was upside down and unfortunately you came to early and i hadn't posted the edited version yet sorry about that xD
    No worries.
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    (Original post by Zacken)
    No worries.
    ok thanks
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    Well done.
 
 
 
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