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# Complex numbers argument Watch

1. http://www.ocr.org.uk/Images/79455-q...atics-3.pdfFor question 2ii of the paper above how would you know how to change the arguments like they have done in the ms below?http://www.ocr.org.uk/Images/97268-m...hematics-3.pdf
2. (Original post by runny4)
http://www.ocr.org.uk/Images/79455-q...atics-3.pdfFor question 2ii of the paper above how would you know how to change the arguments like they have done in the ms below?http://www.ocr.org.uk/Images/97268-m...hematics-3.pdf
The question asks for the arguments in the range 0 to 2pi, so anything outside that range, you multiply/divide as appropriate, by 1, i.e. by .
3. (Original post by ghostwalker)
The question asks for the arguments in the range 0 to 2pi, so anything outside that range, you multiply/divide as appropriate, by 1, i.e. by .
looking at the answers it makes sense but without the answer in front of you how would know how to change (z+e^(-pi/6)) to (z-e^(7pi/6))- what property do you use- the graphs?
4. (Original post by runny4)
looking at the answers it makes sense but without the answer in front of you how would know how to change (z+e^(-pi/6)) to (z-e^(7pi/6))- what property do you use- the graphs?
Those two are not equivalent.

They have switched the order of the factors.

To change a +e^.. to a -e^... they've multipled/divided by

so
5. (Original post by ghostwalker)
Those two are not equivalent.

They have switched the order of the factors.

To change a +e^.. to a -e^... they've multipled/divided by

so
oh thank you

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