I'm gonna cry if I can't answer this question

Silver oxide,Ag2O, can be reduced by passing hydrogen gas over the heated oxide.
The maximum mass of silver that could be obtained from 2.32 g of silver oxide is?

I keep getting 1.79g. It's wrong. Can anyone help? Remember to show your steps so I can see how you worked it out.

Reply 1

W0nker

What's the equation?

I guessed it might be: AgO2 + 2H2 --> Ag + 2H2O

I got 1.38 g using that equation

Reply 2

Siles

Einsteinium

What's the equation?

I guessed it might be: AgO2 + 2H2 --> Ag + 2H2O

I got 1.38 g using that equation

It doesn't give you an equation. The probable equation would be:

Ag2O + H2 --> H2O + 2Ag

You got the Ag2O formula wrong in your above equation.

I worked it out as:

Mr of Ag2O = 70

moles = mass/mr = 2.32/70 = 3.31 x 10^-2

Molar ratio is 1:2, therefore 6.62 x 10^-2 Ag formed.

Ar Ag = 27

mass = 6.62 x 10^-2 x 27 = 1.79 g.

However, the synoptic paper I got this off says this is wrong.

Reply 3

silent ninja

Mr of Ag2O cant possible be 70, silver is 108 on its own!!

Reply 4

silent ninja

So Mr= 232, now look what nice numbers you have.

Reply 5

W0nker

Oh wait I know what I did, read the proton number not mass number oops. Well Ok:

If the equation is: Ag2O + H2 --> H2O + 2Ag

Moles = mass/Mr

Mr Ag2O = 232

Moles Ag2O = 2.32 / 232 = 0.01

2:1 ratio so 0.02 moles of Ag will form

Mass = moles x mr = 0.02 x 108 = 2.16 g

That right?

Reply 6