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    So basically for question 23 (c) I labelled the midpoint of PT as M and the midpoint of OR as N. Then I found the vector MN to be (b-a) and the vector MS to be (b-a)/4. Then I wrote that S divides the line MN in ratio 1:3. Do you think that I can get at least 1 mark or full marks? I got the rest of the paper correct so I was wondering if I am able to get 100/100.
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    (Original post by Ace2233)
    So basically for question 23 (c) I labelled the midpoint of PT as M and the midpoint of OR as N. Then I found the vector MN to be (b-a) and the vector MS to be (b-a)/4. Then I wrote that S divides the line MN in ratio 1:3. Do you think that I can get at least 1 mark or full marks? I got the rest of the paper correct so I was wondering if I am able to get 100/100.
    I don't know what the question actually asked for... do you have any more details?
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    (Original post by Dowel)
    I don't know what the question actually asked for... do you have any more details?
    http://mrkibria.weebly.com/uploads/7..._mr_kibria.pdf

    Question 23 (c)
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    How did you work out MS as 1/4 (b-a) ? The first bit is right btw.
    If you just assumed MS then you will lose a mark.
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    (Original post by Dowel)
    How did you work out MS as 1/4 (b-a) ? The first bit is right btw.
    If you just assumed MS then you will lose a mark.
    I found that MS=MP+PS so MP=-1/2b and PS=1/4(-a+3b)=-1/4a+3/4b. When you add them them you get -1/2b+3/4b-1/4a which then gives you 1/4b-1/4a which can be factorised to (b-a)/4
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    (Original post by Dowel)
    I don't know what the question actually asked for... do you have any more details?
    Is this 2016??? How did you get this paper...I'm in year 10 btw.
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    Do you know where you can get foundation?
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    (Original post by *Alisha*)
    Do you know where you can get foundation?
    Sorry I don't know. I found the paper here on TSR
    http://www.thestudentroom.co.uk/show....php?t=4120523
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    (Original post by Ace2233)
    I found that MS=MP+PS so MP=-1/2b and PS=1/4(-a+3b)=-1/4a+3/4b. When you add them them you get -1/2b+3/4b-1/4a which then gives you 1/4b-1/4a which can be factorised to (b-a)/4
    I just realised the question asks you to use your answer to part b, if it didn't I would say you get full marks but because you haven't used your answer for b you probably won't.
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    (Original post by Dowel)
    I just realised the question asks you to use your answer to part b, if it didn't I would say you get full marks but because you haven't used your answer for b you probably won't.
    I see. Thanks for the help.
 
 
 
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