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Size:  277.6 KBWould anyone be able to show me how to do these questions pls?
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    (Original post by AqsaMx)
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Size:  277.6 KBWould anyone be able to show me how to do these questions pls?
    Your teacher has already shown you in the margin!!!
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    (Original post by charco)
    Your teacher has already shown you in the margin!!!
    I feel like that's what I did though?
    Isn't the H+ conc and conc of the conjugate base the same??
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    (Original post by AqsaMx)
    I feel like that's what I did though?
    Isn't the H+ conc and conc of the conjugate base the same??
    pKa = 4, ka = 1 x 10-4
    pH = 3, [H+] = 1 x 10-3

    ka = [H+][A-]/[HA]

    Hence, the ratio of conjugate base to acid = [A-]/[HA] = ka/[H+] = 1 x 10-4/1 x 10-3 = 1 x 10-1 = 0.1
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    (Original post by charco)
    pKa = 4, ka = 1 x 10-4
    pH = 3, [H+] = 1 x 10-3

    ka = [H+][A-]/[HA]

    Hence, the ratio of conjugate base to acid = [A-]/[HA] = ka/[H+] = 1 x 10-4/1 x 10-3 = 1 x 10-1 = 0.1
    That's the answer I got..
 
 
 
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