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# Acid to conjugate base ratios Watch

1. Would anyone be able to show me how to do these questions pls?
2. (Original post by AqsaMx)
Would anyone be able to show me how to do these questions pls?
3. (Original post by charco)
I feel like that's what I did though?
Isn't the H+ conc and conc of the conjugate base the same??
4. (Original post by AqsaMx)
I feel like that's what I did though?
Isn't the H+ conc and conc of the conjugate base the same??
pKa = 4, ka = 1 x 10-4
pH = 3, [H+] = 1 x 10-3

ka = [H+][A-]/[HA]

Hence, the ratio of conjugate base to acid = [A-]/[HA] = ka/[H+] = 1 x 10-4/1 x 10-3 = 1 x 10-1 = 0.1
5. (Original post by charco)
pKa = 4, ka = 1 x 10-4
pH = 3, [H+] = 1 x 10-3

ka = [H+][A-]/[HA]

Hence, the ratio of conjugate base to acid = [A-]/[HA] = ka/[H+] = 1 x 10-4/1 x 10-3 = 1 x 10-1 = 0.1

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