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    it takes 2000 j of energy to increase the temperature of the brake disc on each wheel by 1 degree C. if the car has a mass of 1 tonne and slows from 20m/s to 15 m/s how much will the disc's temperature rise?
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    (Original post by bilesbilinski)
    it takes 2000 j of energy to increase the temperature of the brake disc on each wheel by 1 degree C. if the car has a mass of 1 tonne and slows from 20m/s to 15 m/s how much will the disc's temperature rise?
    Popped this in the Physics thread for you
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    (Original post by bilesbilinski)
    it takes 2000 j of energy to increase the temperature of the brake disc on each wheel by 1 degree C. if the car has a mass of 1 tonne and slows from 20m/s to 15 m/s how much will the disc's temperature rise?
    What is the change in the car's kinetic energy as it slows from 20m/s to 15m/s? Remember, KE = 1/2mv^2.

    You can then work out how much the temperature of the brake discs will rise. For example, if the car's KE changed by 8000J, then that would be 2000J per brake disc and therefore each disc's temperature will rise by 1 degree C.
 
 
 
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