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    NH3(CHCl3) -->/<-- NH3(aq)

    75 cm3 of 4.0 mol dm–3 aqueous ammonia solution and 75 cm3 of the trichloromethane are shaken together. The two liquids are allowed to separate and 25.0cm3 of the aqueous layer is taken and titrated with 4.0 mol dm–3 hydrochloric acid. The whole procedure is repeated. The average titre is 24.0 cm3.

    It asks you to calculate the concentration of ammonia in the aqueous layer which I did which is 3.84moldm-3.

    Then it asks:

    The initial volumes of the two solvents are the same. Hence deduce the concentration of ammonia in the trichloromethane layer in mol dm–3

    The answer is 0.16moldm-3, I don't understand the maths or the logic behind why that is the answer, if you could help me understand I would be very grateful
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    this is the January 2014 IAL paper, Q18ciii if you were wondering where I got the question from
 
 
 
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