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    Calculate the number of possible combinations of chromosomes if the diploid number is four? Assume there is no crossing over of chromosomes.

    Many thanks.
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    4 is the answer.
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    (Original post by Gav107)
    4 is the answer.
    Can you explain how you got this please?
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    The options given are: (from what i remember)

    16,
    256,
    32,
    64
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    Diploid number is 4 so there's two pairs. So 2^2 =4
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    Nope, 16 was what i thought....
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    the answer is 16

    4/2 = 2
    (2^2) = 4
    4^2 = 16
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    16
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    I thought the formula given in the textbook is (2^n)^2

    So the answer is (2*2*2*2)^2 = 16^2 = 256
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    n stands for the homologous chromosome pairs. Here they've given only the number of chromosomes (being 4) in the cell.
 
 
 
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