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# Diluting solutions question Watch

1. 50cm^3 of 3.0m hydrochloric acid was diluted with 150cm3 of water. What is the concentration of hydrogen ions in the resultant solution?
2. (Original post by Idontlikeict)
50cm^3 of 3.0m hydrochloric acid was diluted with 150cm3 of water. What is the concentration of hydrogen ions in the resultant solution?
... and your ideas are?
3. (0.05)(3.0) = 0.2 mol

0.2 mol/0.15dm^3 = 1.3 mol/dm^3 or 1300 mol/cm^3

?
4. the answer is 0.75mol/dm^-3 however, i don't know how to get this
5. (Original post by Idontlikeict)
50cm^3 of 3.0m hydrochloric acid was diluted with 150cm3 of water. What is the concentration of hydrogen ions in the resultant solution?
Okay so the new volume of the solution is 200cm^3.
There's a formula.
c1v1 = c2v2

50 x 3 = 200 x new concentration

new conc. = 150/200

=0.75
6. (Original post by hamza.sheikh)
Okay so the new volume of the solution is 200cm^3.
There's a formula.
c1v1 = c2v2

50 x 3 = 200 x new concentration

new conc. = 150/200

=0.75
i was somewhat close to this but i didn't think of dividing 150/200, thanks for the help!

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