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    50cm^3 of 3.0m hydrochloric acid was diluted with 150cm3 of water. What is the concentration of hydrogen ions in the resultant solution?
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    (Original post by Idontlikeict)
    50cm^3 of 3.0m hydrochloric acid was diluted with 150cm3 of water. What is the concentration of hydrogen ions in the resultant solution?
    ... and your ideas are?
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    (0.05)(3.0) = 0.2 mol

    0.2 mol/0.15dm^3 = 1.3 mol/dm^3 or 1300 mol/cm^3

    ?
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    the answer is 0.75mol/dm^-3 however, i don't know how to get this
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    (Original post by Idontlikeict)
    50cm^3 of 3.0m hydrochloric acid was diluted with 150cm3 of water. What is the concentration of hydrogen ions in the resultant solution?
    Okay so the new volume of the solution is 200cm^3.
    There's a formula.
    c1v1 = c2v2

    50 x 3 = 200 x new concentration

    new conc. = 150/200

    =0.75
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    (Original post by hamza.sheikh)
    Okay so the new volume of the solution is 200cm^3.
    There's a formula.
    c1v1 = c2v2

    50 x 3 = 200 x new concentration

    new conc. = 150/200

    =0.75
    i was somewhat close to this but i didn't think of dividing 150/200, thanks for the help!
 
 
 
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