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Differentiation

Differentiate tan(5x^2+3)
Would it be 10xsec^2 (5x^2+3)
@English-help
Use chain rule.
u=5x2+3u=5x^{2}+3
dudx=10x\frac{du}{dx}=10x
y=tan(u)y=\tan(u)
dydu=sec2(u)\frac{dy}{du}=\sec^{2}(u)
dydx=dydududx=10xsec2(u)=10xsec2(5x2+3)\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}=10x\sec^{2}(u)=10x\sec^{2}(5x^{2}+3)
Original post by English-help
Would it be 10xsec^2 (5x^2+3)

You are correct.

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