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    Hi, I am struggling with question 10 (ii) on the June 2006 OCR MEI paper. I've got as far as theta = 2 radians and I know that this is 114.6 degrees. I don't know how to go from there.
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    The original bearing was 48 degrees. So the ship has gone 114.6 degrees from this bearing in an anticlockwise direction. So this is (114.6 - 48) = 66.6 degrees ANTIclockwise from north. But remember that bearings are always taken CLOCKWISE from North so this new bearing will be (360 - 66.6) = 293.4 degrees.
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    (Original post by Teenie2)
    The original bearing was 48 degrees. So the ship has gone 114.6 degrees from this bearing in an anticlockwise direction. So this is (114.6 - 48) = 66.6 degrees ANTIclockwise from north. But remember that bearings are always taken CLOCKWISE from North so this new bearing will be (360 - 66.6) = 293.4 degrees.
    ahh yes! was just looking how to do this question and I didn't realise it was anticlockwise!
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    (Original post by Teenie2)
    The original bearing was 48 degrees. So the ship has gone 114.6 degrees from this bearing in an anticlockwise direction. So this is (114.6 - 48) = 66.6 degrees ANTIclockwise from north. But remember that bearings are always taken CLOCKWISE from North so this new bearing will be (360 - 66.6) = 293.4 degrees.
    Oh I'd forgotten that they'd given you the 48 degrees in the first part... Thanks for your help
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    just was doing this paper now as a test, and was getting 302.4, this makes more sense now
 
 
 
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