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    Can someone please do and explain part c and d

    I keep getting an answer of 80 secs when it's meant to be 50(?)
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    (Original post by CrystalPark)
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    Can someone please do and explain part c and d

    I keep getting an answer of 80 secs when it's meant to be 50(?)
    The bike passes the car when the car has travelled 990m. Work out the time the car has done that.

    (30x22)/2 + (22xt) = 990 (30x22)=330 so (22xt) =660 so t=30

    30 + 30 = 60.

    As the bike started later and caught up at t=60, it is 10 seconds faster then the car, so deduct 10 to get 50.

    as for part d, you will know the total time and distance, so you can work out acceleration

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    (Original post by KloppOClock)
    The bike passes the car when the car has travelled 990m. Work out the time the car has done that.

    (30x22)/2 + (22xt) = 990 (30x22)=330 so (22xt) =660 so t=30

    30 + 30 = 60

    As the bike started later and caught up at t=60, it is 10 seconds faster then the car, so deduct 10 to get 50.

    as for part d, you will know the total time and distance, so you can work out acceleration

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    THANK YOU SO MUCH!!! 👌🏻💯👌🏻💯
    This has really helped!!

    But one quick question
    How comes you can't find the area of the bike??
    As in if you did (22t/2)=990
    Coz that gives me the answer of 80
    But why would this not work??
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    (Original post by CrystalPark)
    THANK YOU SO MUCH!!! 👌🏻💯👌🏻💯
    This has really helped!!

    But one quick question
    How comes you can't find the area of the bike??
    As in if you did (22t/2)=990
    Coz that gives me the answer of 80
    But why would this not work??
    the bike doesnt necessarily pass the car at 22m/s it passes the car at 990m. Two vehicles can be at the same distance at the same point of time but going at different speeds if they set off at different times.

    The mark scheme explicity states that this is a common error when working out c
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    (Original post by KloppOClock)
    the bike doesnt necessarily pass the car at 22m/s it passes the car at 990m. Two vehicles can be at the same distance at the same point of time but going at different speeds if they set off at different times.

    The mark scheme explicity states that this is a common error when working out c
    Oooooh I see
    Thank you so much once again 👌🏻👌🏻
 
 
 
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