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# negative simultaneous equations?! Watch

1. hey guys!
so i can do simultaneous equations fairly well and i always find when i get to the end both factors are often negative. when this happens can i just turn the both positive?? will it still work?
2. (Original post by gertygreengage)
hey guys!
so i can do simultaneous equations fairly well and i always find when i get to the end both factors are often negative. when this happens can i just turn the both positive?? will it still work?

If you had (6-x)(3-2x) = 0, then you can take out a factor of -1 from each break to give (x-6) * -1 * -1 * (2x-3) so you also get that (x-6)(2x-3) = 0.

You can also take out -1 in things like (5-x)(x+3) = 0 to give -1 * (x-5)(x+3) = 0 , then divide both sides by -1 to give (x-5)(x+3) = 0.
3. (Original post by SeanFM)

If you had (6-x)(3-2x) = 0, then you can take out a factor of -1 from each break to give (x-6) * -1 * -1 * (2x-3) so you also get that (x-6)(2x-3) = 0.

You can also take out -1 in things like (5-x)(x+3) = 0 to give -1 * (x-5)(x+3) = 0 , then divide both sides by -1 to give (x-5)(x+3) = 0.
oh right!! ok thanks!!

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