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    ethnoic acid dissolves in aqueous solution


    predict and explain the effect on the position of the equilibrium of dissolving sodium ethanoate ( a souse of ch3cooh ions) in dilute ethnoic acid.

    can someone explain which does this shift to the left

    More ethanoate ions are produced as sodium ethanoate dissociates into CH3COO- and Na+. This means that the equilibrium shifts to oppose the increase of ch3coo- ions so favours the backwards reaction (more ethanoic acid produced) meaning the equiliobrium shifts to the left

    ok so your equilibrium is:
    CH3COOH⇌CH3COO- + h+

    If you add CH3COO- ions, ie increase the concentration, the equilibrium will shift to counteract that change by decreasing the concentration of CH3COO- ions by reacting the ethanoate ions with hydrogen ions to produce ethanoic acid. This means your equilibrium has shifted to the left because you increase the concentration of ethanoic acid.
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