mrpaper
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hi,
in bounds sometimes they ask you to

'By considering bounds, work out the value of A to a suitable degree of accuracy'

what does it mean by a suitable degree of accuracy?
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qwerty0301
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(Original post by mrpaper)
hi,
in bounds sometimes they ask you to

'By considering bounds, work out the value of A to a suitable degree of accuracy'

what does it mean by a suitable degree of accuracy?
basically have to write out the UB and LB and see up to what number of significant figures they both agree to.
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Hannxhq
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(Original post by mrpaper)
hi,
in bounds sometimes they ask you to

'By considering bounds, work out the value of A to a suitable degree of accuracy'

what does it mean by a suitable degree of accuracy?
It means that if you got a number after you applied the bounds where it was like 4.57685994474748384747477... etc
then you should round it to either 1,2 or 3 decimal places ie. 4.58(2.dp)
just make sure you specify the fact that it's 2.dp
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Arcaddia
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Yea, as others have said. It says suitable so that should mean to you simply as: not a stupid number, As the guy above me said 4.57768843753287358 blah blah, just round it to 1dp or even 2dp which ever. As that is suitable.
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username2437011
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(Original post by mrpaper)
hi,
in bounds sometimes they ask you to

'By considering bounds, work out the value of A to a suitable degree of accuracy'

what does it mean by a suitable degree of accuracy?
Hi, basically it would give you an equation, you need to work out the upper bound and the lower bound of the equation, both answers would be similar to a certain point, you just need to write the answer up to that point.

For example: The lower bound of an equation =1.7094... and the lower bound= 1.7091..., then your answer to a suitable degree of accuracy would be 1.709.

Note: if the answer can be rounded for example if the lower bound was 1.7095..., then your answer would be 1.71 instead of 1.709 because 1.7095 can be rounded to 1.780.

Hope that made sense.

Edit: also state how many decimal places.
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ksj.11
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work out upper bound and lower bound and round the answer to a answer that is matched by both upper and lower bounds so

if lb is 0.287 and ub is 0.293221

round to 0.29 (2dp) as both ub and lb round to this value


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