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    How do you find maximum mass of precipitate?

    What i did so far was that I worked out the moles:
    100/1000 x 0.500= 0.05 moles
    • moles x Mr = Mass

    Now when it comes to Mr, is it the Mr of silver nitrate or calcium chloride?
    I have tried both ways but my answer didn't match any of the options given?
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    is the answer 8.95g?
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    (Original post by huggleberry247)
    is the answer 8.95g?
    nope! That's what I thought but it's 7.17 g ?!
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    Adorable98

    Moles=Mass/Mr

    AgCl is the ppt, think of the silver nitrate test for chloride ions, white ppt is produced.

    So 100/1000 x 0.05

    ANS^ x (107.9+35.5) = 7.17g
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    (Original post by Engineerrookie)
    Remember moles = mass / Mr

    AgCl is the ppt, think of the silver nitrate test for chloride ions, white ppt is produced.

    So 100/1000 x 0.05

    ANS^ x (107.9+35.5) = 7.17g
    Oh I see!! Thank you!!
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    (Original post by Adorable98)
    Oh I see!! Thank you!!

    No problem! Good luck tomorrow!
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    (Original post by Engineerrookie)
    No problem! Good luck tomorrow!
    Thank you!!
 
 
 
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