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# C3 Algebraic fractions watch

1. In the attachment below this is given
(in the "where things can go ugly" section)
Blindly multiplying the two denominators when there might be a common factor, e.g. (𝑥+3)(𝑥−3) and (𝑥+3) should become (𝑥+3)(𝑥−3) rather than (𝑥+3)²(𝑥−3).

But surely multiplying
(x+3)(x-3) by (x+3) would give (x-3)²(x-3)????
Attached Images
2. C3CheatSheet.pdf (418.4 KB, 106 views)
3. If you're adding 2 fractions, say then you're going to end up with which is unnecessary because there's a common factor of (x+3) in the fraction. So it just ends up as
Unparseable or potentially dangerous latex formula. Error 4: no dvi output from LaTeX. It is likely that your formula contains syntax errors or worse.
\frac{A+B(x-3)}{(x+3)(x-3)

fml.. Latex is broken at the moment I think.

edit:
4. (Original post by Parallex)
If you're adding 2 fractions, say then you're going to end up with which is unnecessary because there's a common factor of (x+3) in the fraction. So it just ends up as

fml.. Latex is broken at the moment I think.

edit:
But the question is ....
oh i forgot the definition of denominator xD silly me thanks anyway

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