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    Can anyone help me on this question? I'm not sure if it is a typo or because it doesn't have have squared?Name:  ImageUploadedByStudent Room1465567282.473212.jpg
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    Need help on the second part of this question? Do I multiply the function by two and then solve?
    Name:  ImageUploadedByStudent Room1465567882.585012.jpg
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    (Original post by BobbiBlue)
    Can anyone help me on this question? I'm not sure if it is a typo or because it doesn't have have squared?Name:  ImageUploadedByStudent Room1465567282.473212.jpg
Views: 58
Size:  39.8 KB


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    It's definitely a typo, you can't turn a quadratic into a linear expression by multiplying and adding constants, assuming a, b and c are just constants.
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    I would try to help you but I failed my exam :/
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    (Original post by BobbiBlue)
    Need help on the second part of this question? Do I multiply the function by two and then solve?
    Name:  ImageUploadedByStudent Room1465567882.585012.jpg
Views: 60
Size:  54.3 KB


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    g(2x) just means replace every x from g(x) with (2x)
    so you get

    g(2x) = (2x + 6) / 4x

    Now the problem is very similar to the first part of the problem
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    (Original post by samspedding)
    It's definitely a typo, you can't turn a quadratic into a linear expression by multiplying and adding constants, assuming a, b and c are just constants.
    Good because I can do that ahaha, just wanted to make sure that you couldn't do it


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    (Original post by U-GradeStudent)
    I would try to help you but I failed my exam :/
    I'm sorry to hear that thanks for replying though


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    (Original post by samspedding)
    g(2x) just means replace every x from g(x) with (2x)
    so you get

    g(2x) = (2x + 6) / 4x

    Now the problem is very similar to the first part of the problem
    That seems really easy now, thank you very much


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    (Original post by BobbiBlue)
    I'm sorry to hear that thanks for replying though


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    It's cool
 
 
 
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