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    How would you integrate this?


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    It is of the form f'(x)/f(x).
    Which integrates to ln|f(x)| (+c)
    There's only a very slight difference that it's multiplied by a constant, 3. But you can just take this to the left hand side of the integral.
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    (Original post by rpnom)
    How would you integrate this?


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    Move the 3 outside the integral sign, then it's just f'(x) / f(x)
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    let u = 2x^2 - x + 2
    dx/du = 1/(4x-1)

    giving you the integral of
    3/u du

    -> 3ln(u) + c
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    Take the 3 from the '3(4x-1)' outside the integral then integrate using the f'(x)/f(x) rule.
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    Nice to know people agree with me.
 
 
 
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