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# Help C2 AQA watch

1. Need help on this question, ive been going round in circles for some time
2. (Original post by Sniperdon227)

Need help on this question, ive been going round in circles for some time
Right, off, you know that c = 3^m and d = 27^n = (3^3)^n = 3^(3n).

So sqrt(c) = 3^(m/2) and d^2 = 3^(6n).

Can you now compute sqrt(c) / d^2?

Hint: 3^a / 3^b = 3^(a-b)
3. (Original post by Zacken)
Right, off, you know that c = 3^m and d = 27^n = (3^3)^n = 3^(3n).

So sqrt(c) = 3^(m/2) and d^2 = 3^(6n).

Can you now compute sqrt(c) / d^2?

Hint: 3^a / 3^b = 3^(a-b)
thats exactly what I did so 3^(-11n/2)
4. (Original post by Sniperdon227)
thats exactly what I did so 3^(-11n/2)
1. If that's what you did, why didn't you post it in the first place? That'd have been more helpful for the both of us.

2. How on earth did you get that? You have 3^(m/2) in the numerator and 3^(6n) in the denominator, so dividing them gets a power of m/2 - 6n.

m and n are different letters. i.e: m =/= n.
5. (Original post by Zacken)
1. If that's what you did, why didn't you post it in the first place? That'd have been more helpful for the both of us.

2. How on earth did you get that? You have 3^(m/2) in the numerator and 3^(6n) in the denominator, so dividing them gets a power of m/2 - 6n.

m and n are different letters. i.e: m =/= n.
thats what happens when i do maths in the morning, im going sleep, so is that the final answer? the ms is not available as its the 2016
6. (Original post by Sniperdon227)
thats what happens when i do maths in the morning, im going sleep, so is that the final answer? the ms is not available as its the 2016
Yes.

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