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    Anyone has a step by step guide on how to rearrange the following equation to make a the subject of the formula:

    a + 3 = ( 2a + 7) / r

    Thanks!
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    Multiply by r, the. Get all the terms with a on one side of the equation and take out a factor of a. Should be clear what to do then.
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    (Original post by B_9710)
    Multiply by r, the. Get all the terms with a on one side of the equation and take out a factor of a. Should be clear what to do then.
    I found the mark scheme and it says that the answer is:
    a = (7 - 3r) / (r - 2)
    HOW!!!
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    (Original post by NothingButWaleed)
    Anyone has a step by step guide on how to rearrange the following equation to make a the subject of the formula:

    a + 3 = ( 2a + 7) / r

    Thanks!
    1) Multiply by r....ar+3r = 2a + 7
    2)Bring the ones with a to oneside... ar-2a=7-3r
    3) Factor out the a....... a(r-2) = (7-3r)
    4) Divide by the (r-2) to get a alone... a= (7-3r) / (r-2)
 
 
 
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