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A2 Physics A Turning points: photo electricity question watch

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    How do I do (b) and (c)? Topic 2.3 Turning points (OPTION D)

    2. When a metal surface is illuminated with light of wavelength 410 nm, photoelectrons are emitted with amaximum kinetic energy of 2.10 × 10−19 J.Calculate:
    a the energy of a photon of this wavelength
    b the work function of the metal surface
    c the stopping potential for this surface illuminated by light of wavelength 410 nm

    So for part
    (a) E=hc/lambda =(6.63*10^-34)*(3*10^8)/410*10^-9
    E=4.85*10^-19 j

    then I thought
    (b) work function = hf - Ek
    =4.85*10^-19 - 2.10*10^-19
    = 2.75*10^-19

    but this is wrong textbook answer is 1.61*10^-19j

    What am I doing wrong?
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    help with unit 2 physics AQA?
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    (Original post by smitj893)
    help with unit 2 physics AQA?
    You are going to want to go here http://www.thestudentroom.co.uk/forumdisplay.php?f=131 and press "post new thread" then ask your question
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    (Original post by Music With Rocks)
    How do I do (b) and (c)? Topic 2.3 Turning points (OPTION D)

    2. When a metal surface is illuminated with light of wavelength 410 nm, photoelectrons are emitted with amaximum kinetic energy of 2.10 × 10−19 J.Calculate:
    a the energy of a photon of this wavelength
    b the work function of the metal surface
    c the stopping potential for this surface illuminated by light of wavelength 410 nm

    So for part
    (a) E=hc/lambda =(6.63*10^-34)*(3*10^8)/410*10^-9
    E=4.85*10^-19 j

    then I thought
    (b) work function = hf - Ek
    =4.85*10^-19 - 2.10*10^-19
    = 2.75*10^-19

    but this is wrong textbook answer is 1.61*10^-19j

    What am I doing wrong?
    I don't think you are doing anything wrong in part b. I think the textbook answer is wrong. I have the same book and it seems to be an error,

    Part (c). The stopping potential is when eV = Ek max

    So 2.1x10-19 / e = V = 1.3125 V
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    (Original post by SirRaza97)
    I don't think you are doing anything wrong in part b. I think the textbook answer is wrong. I have the same book and it seems to be an error,

    Part (c). The stopping potential is when eV = Ek max

    So 2.1x10-19 / e = V = 1.3125 V
    Ah thank you very much, that question was stressing me out :P annoying how often the textbook answers are wrong.
 
 
 
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