I can literally do all of them but I can't seem to understand this one??
http://prntscr.com/bgeogr
Thanks

Chickenslayer69
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 14062016 21:13

16characterlimit
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 14062016 21:23
Not 100% sure, but arcsin(0) = 0
0 + 2(pi)n = x + pi/6
x = 2pi(n)  pi/6
The n is because sin is periodic every 2pi radians, this is my interpretation of the answer but a markscheme would be nice to check if this is what your question wants.Last edited by 16characterlimit; 14062016 at 21:33. 
Math12345
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 14062016 21:24
Sin(x+pi/6)=0
x+pi/6= pi*n where n is an integer (this is obvious using the graph of sin i.e you should know sinx is 0 when x=0,pi,2pi,3pi,....)
x= pi/6 +pi*nLast edited by Math12345; 14062016 at 21:30. 
IrrationalRoot
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 14062016 21:30
(Original post by 16characterlimit)
Not 100% sure, but arcsin(0) = 0 +(2pi)n where n is a integer.
0 + 2(pi)n = x + pi/6
x = 2pi(n)  pi/6
The n is because sin is periodic every 2pi radians, this is my interpretation of the answer but a markscheme would be nice to check if this is what your question wants.
If you're saying what you've highlighted in bold, what you mean is that any number with sine 0 is (for some ).
FFS what's wrong with Latex.Last edited by IrrationalRoot; 14062016 at 21:31. 
Chickenslayer69
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 14062016 21:31
QUOTE=16characterlimit;65785569]Not 100% sure, but arcsin(0) = 0 +(2pi)n where n is a integer.
0 + 2(pi)n = x + pi/6
x = 2pi(n)  pi/6
The n is because sin is periodic every 2pi radians, this is my interpretation of the answer but a markscheme would be nice to check if this is what your question wants.[/QUOTE]
Yes, I got x = 2pi(n) pi/6 but the mark scheme says x = pi(n)  pi/6, I'm not sure if both are accepted?
I think I could maybe work it out now by considering x + pi/6 as a translation to the left by pi/6. If you look at the graph the answer is computed for every pi(n)  pi/6, but I don't understand how to get the answer if I'm not doing it like that. 
Chickenslayer69
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 14062016 21:32
QUOTE=Math12345;65785619]Sin(x+pi/6)=0
x+pi/6= pi*n where n is an integer (this is obvious using the graph of sin i.e you should know sinx is 0 when x=0,pi,2pi,3pi,....)
x= pi/6 +pi*n[/QUOTE]
So pi*n is used when sinx is 0, but for any other value 2*pi*n is used? 
Math12345
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 14062016 21:33
If siny=0 then y=pi*n this should be obvious to you. Then just let y=x+pi/6 and rearrange.

16characterlimit
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 14062016 21:34
(Original post by IrrationalRoot)
Yeah this isn't true. If this was the case then arcsin would not be a function. It has a restricted range so that it is a function, namely .
If you're saying what you've highlighted in bold, what you mean is that any number with sine 0 is (for some ).
FFS what's wrong with Latex.
OK I removed the offending section. 
Math12345
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 14062016 21:37
(Original post by Chickenslayer69)
QUOTE=Math12345;65785619]Sin(x+pi/6)=0
x+pi/6= pi*n where n is an integer (this is obvious using the graph of sin i.e you should know sinx is 0 when x=0,pi,2pi,3pi,....)
x= pi/6 +pi*n
Here's the general approach:
sin(x+pi/6)=0
x+pi/6=0,pi (2 initial solutions when solving for sin)
x=pi/6, x=5pi/6
x=pi/6 +2pi*n , x=5pi/6+2pi*n
Write out a few solutions,
x=pi/6, 11pi/6, 5pi/6 , 17pi/6
Should be obvious general solution is x=pi/6+pi*n from that. 
Chickenslayer69
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 14062016 21:40
QUOTE=Math12345;65786111]So pi*n is used when sinx is 0, but for any other value 2*pi*n is used?[/QUOTE]
Here's the general approach:
sin(x+pi/6)=0
x+pi/6=0,pi (2 initial solutions when solving for sin)
x=pi/6, x=5pi/6
x=pi/6 +2pi*n , x=5pi/6+2pi*n
Write out a few solutions,
x=pi/6, 11pi/6, 5pi/6 , 17pi/6
Should be obvious general solution is x=pi/6+pi*n from that.[ QUOTE]
Ohh, ok, got it. Thanks
I actually did this first but didn't substitute for n so didn't realize it could be simplified to x = pi/6 + pi*n... I will remember next time.Last edited by Chickenslayer69; 14062016 at 21:41. 
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 16062016 09:37
(Original post by Chickenslayer69)
I can literally do all of them but I can't seem to understand this one??
http://prntscr.com/bgeogr
Thanks
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