# TITRATION CALCULATIONS! C3 please help

Watch
please can someone list a method of finding titration calculations?

the CGP book and my-gcsescience.com do it different ways and i'm so confused

thank you!

the CGP book and my-gcsescience.com do it different ways and i'm so confused

thank you!

0

reply

Report

#2

I learn the equation:

Moles = concentration X volume

ALWAYS remember If you're given a volume in cm*3 then divide it by 1000 to get it into dm*3

Firstly find out whatever you can from the information they provide, they usually give the concentration and volume so you can work out the moles

The moles is the same for both the reactants so substitute the moles into the equation to find the missing concentration/volume

Concentration is: moles divided by volume

Volume: moles divided my concentration

It's so hard to explain by typing 😂

Posted from TSR Mobile

Moles = concentration X volume

ALWAYS remember If you're given a volume in cm*3 then divide it by 1000 to get it into dm*3

Firstly find out whatever you can from the information they provide, they usually give the concentration and volume so you can work out the moles

The moles is the same for both the reactants so substitute the moles into the equation to find the missing concentration/volume

Concentration is: moles divided by volume

Volume: moles divided my concentration

It's so hard to explain by typing 😂

Posted from TSR Mobile

1

reply

Report

#3

(Original post by

I learn the equation:

Moles = concentration X volume

ALWAYS remember If you're given a volume in cm*3 then divide it by 1000 to get it into dm*3

Firstly find out whatever you can from the information they provide, they usually give the concentration and volume so you can work out the moles

The moles is the same for both the reactants so substitute the moles into the equation to find the missing concentration/volume

Concentration is: moles divided by volume

Volume: moles divided my concentration

It's so hard to explain by typing 😂

Posted from TSR Mobile

**z1820**)I learn the equation:

Moles = concentration X volume

ALWAYS remember If you're given a volume in cm*3 then divide it by 1000 to get it into dm*3

Firstly find out whatever you can from the information they provide, they usually give the concentration and volume so you can work out the moles

The moles is the same for both the reactants so substitute the moles into the equation to find the missing concentration/volume

Concentration is: moles divided by volume

Volume: moles divided my concentration

It's so hard to explain by typing 😂

Posted from TSR Mobile

Posted from TSR Mobile

0

reply

Report

#4

(Original post by

please can someone list a method of finding titration calculations?

the CGP book and my-gcsescience.com do it different ways and i'm so confused

thank you!

**jazz_xox_**)please can someone list a method of finding titration calculations?

the CGP book and my-gcsescience.com do it different ways and i'm so confused

thank you!

Think of it as a neutralisation equation

25cm3 of 0.1 moldm3 HCI reacts with 22.5cm3 of NaOH

NaOH + HCI ----- NaCI + H2O

1) ensure equation is balanced.

2) I usually next write out a table, the two headings are the reactants: moles, volume and concentration need to be worked out.

Considering your always given the concentration and volume one reactant you can work out the number of moles. In the example: moles = conc X volume (0.1 X (25/1000) = 0.0025 moles

3) work out moles of other reactant. This is done by looking at the big numbers in front of the reactants 1HCI reacts with 1NaOH. Therefore there is a 1:1 ratio and the number of moles of HCI = moles of NaOH

Now you have NaOH moles (and given volume of 22cm3) you can work out concentration

0.0025/0.0022=1.13 moldm3 I think the working out is right but the method definitely is

Just remember your always given the volume and concentration of one. Multiply them to get moles. Use balanced equation to work out the number of moles of other reactant which you can then divide to work out either the concentration or volume

Hope this helped

2

reply

**z1820**)

I learn the equation:

Moles = concentration X volume

ALWAYS remember If you're given a volume in cm*3 then divide it by 1000 to get it into dm*3

Firstly find out whatever you can from the information they provide, they usually give the concentration and volume so you can work out the moles

The moles is the same for both the reactants so substitute the moles into the equation to find the missing concentration/volume

Concentration is: moles divided by volume

Volume: moles divided my concentration

It's so hard to explain by typing 😂

Posted from TSR Mobile

could you write down for the acid and alkali

concentration x volume = concentration x volume

because the moles are the same for each side? (this is if they want you to find a missing concentration or volume?)

thanks again

0

reply

Report

#6

E.g.

2Na + 1Li

They don't have the same number of moles, Na has twice has many - say if you work out the moles of Sodium (Na) is 0.4 all you have to do is divide by 2 to get lithium (because it's half)

Posted from TSR Mobile

0

reply

Report

#7

(Original post by

thank you very much! this is how the my-gcsescience guy does it, but the text book confused me!

could you write down for the acid and alkali

concentration x volume = concentration x volume

because the moles are the same for each side? (this is if they want you to find a missing concentration or volume?)

thanks again

**jazz_xox_**)thank you very much! this is how the my-gcsescience guy does it, but the text book confused me!

could you write down for the acid and alkali

concentration x volume = concentration x volume

because the moles are the same for each side? (this is if they want you to find a missing concentration or volume?)

thanks again

forgot to mention that the moles is the same if they both have the same number behind their formula

E.g.

2Na + 1Li

They don't have the same number of moles, Na has twice has many - say if you work out the moles of Sodium (Na) is 0.4 all you have to do is divide by 2 to get lithium (because it's half)

Posted from TSR Mobile

0

reply

(Original post by

SORRY! (edit)

forgot to mention that the moles is the same if they both have the same number behind their formula

E.g.

2Na + 1Li

They don't have the same number of moles, Na has twice has many - say if you work out the moles of Sodium (Na) is 0.4 all you have to do is divide by 2 to get lithium (because it's half)

Posted from TSR Mobile

**z1820**)SORRY! (edit)

forgot to mention that the moles is the same if they both have the same number behind their formula

E.g.

2Na + 1Li

They don't have the same number of moles, Na has twice has many - say if you work out the moles of Sodium (Na) is 0.4 all you have to do is divide by 2 to get lithium (because it's half)

Posted from TSR Mobile

0

reply

Report

#9

(Original post by

thank you ! would we be able to do a question together so i can be confident im doing it right?

**jazz_xox_**)thank you ! would we be able to do a question together so i can be confident im doing it right?

Posted from TSR Mobile

0

reply

0

reply

(Original post by

27.5 cm3 of 0.2 mol/dm3 hydrochloric acid is needed to titrate 25.0 cm3 of sodium hydroxide solution. What is the concentration of the sodium hydroxide solution?

**jazz_xox_**)27.5 cm3 of 0.2 mol/dm3 hydrochloric acid is needed to titrate 25.0 cm3 of sodium hydroxide solution. What is the concentration of the sodium hydroxide solution?

0

reply

Report

#12

(Original post by

I got 0.22 mol/dm^3

**jazz_xox_**)I got 0.22 mol/dm^3

Me too! (I hope it's right hahah)

Posted from TSR Mobile

0

reply

0

reply

Report

#15

(Original post by

Yay! thank you so much for your help, actually want one of these to come up now! good luck in your exam

**jazz_xox_**)Yay! thank you so much for your help, actually want one of these to come up now! good luck in your exam

Posted from TSR Mobile

0

reply

(Original post by

No problem, well done for learning so fast - they're really tricky! I think at least one question will come up on titration calculations & thank you, good luck to you too

Posted from TSR Mobile

**z1820**)No problem, well done for learning so fast - they're really tricky! I think at least one question will come up on titration calculations & thank you, good luck to you too

Posted from TSR Mobile

0

reply

Report

#17

(Original post by

I think where I was going wrong is I wasn't dividing by 1000 first

**jazz_xox_**)I think where I was going wrong is I wasn't dividing by 1000 first

Are you feeling prepared for the exams?

Posted from TSR Mobile

0

reply

(Original post by

Oh I see ahaha

Are you feeling prepared for the exams?

Posted from TSR Mobile

**z1820**)Oh I see ahaha

Are you feeling prepared for the exams?

Posted from TSR Mobile

also someone just posted this question could you help? its fine if you dont want to its getting late

The equation for the reaction is

CaCO3(s) → CaO(s) + CO2(g)

Calculate the maximum mass of calcium oxide that can be obtained by

heating 25 tonnes of calcium carbonate.

(Relative atomic masses: C = 12, O = 16, Ca = 40)

[The answer is 25 (tonnes) gives 56x25 (tonnes)]

0

reply

Report

#19

(Original post by

Kind of, I'm nervous for C2 tbh because we have only had one (yes, one) lesson on C3 so I've been teaching myself that- but I got an A* in my C2 mock so fingers crossed! are you?

also someone just posted this question could you help? its fine if you dont want to its getting late

The equation for the reaction is

CaCO3(s) → CaO(s) + CO2(g)

Calculate the maximum mass of calcium oxide that can be obtained by

heating 25 tonnes of calcium carbonate.

(Relative atomic masses: C = 12, O = 16, Ca = 40)

[The answer is 25 (tonnes) gives 56x25 (tonnes)]

**jazz_xox_**)Kind of, I'm nervous for C2 tbh because we have only had one (yes, one) lesson on C3 so I've been teaching myself that- but I got an A* in my C2 mock so fingers crossed! are you?

also someone just posted this question could you help? its fine if you dont want to its getting late

The equation for the reaction is

CaCO3(s) → CaO(s) + CO2(g)

Calculate the maximum mass of calcium oxide that can be obtained by

heating 25 tonnes of calcium carbonate.

(Relative atomic masses: C = 12, O = 16, Ca = 40)

[The answer is 25 (tonnes) gives 56x25 (tonnes)]

25 tonnes -------> ?

Mr: (adding all the relative atomic masses)

CaCo3----->CaO

100 ------> 56

100 X 0.56 = 56

So 25 X 0.56 = 14

0.56 X 25 = 14 tonnes ?

Posted from TSR Mobile

0

reply

(Original post by

Hmmm there's 2 ways but:

25 tonnes -------> ?

Mr: (adding all the relative atomic masses)

CaCo3----->CaO

100 ------> 56

100 X 0.56 = 56

So 25 X 0.56 = 14

0.56 X 25 = 14 tonnes ?

Posted from TSR Mobile

**z1820**)Hmmm there's 2 ways but:

25 tonnes -------> ?

Mr: (adding all the relative atomic masses)

CaCo3----->CaO

100 ------> 56

100 X 0.56 = 56

So 25 X 0.56 = 14

0.56 X 25 = 14 tonnes ?

Posted from TSR Mobile

you are actually a life saver for helping me!! i'm getting off TSR now so good luck tomorrow i'm sure you'll do amazing

0

reply

X

### Quick Reply

Back

to top

to top