Say you have....
Li(aq) + H(g) ---> LiH(g)
This is purely hypothetical but because there are the same amount of moles of gas on each side does that mean there is no yield change, or does this include liquids as well so it shifts to the right?
Pressure at equilibrium Watch
- Thread Starter
- 15-06-2016 10:52
- 15-06-2016 16:07
from my understanding (what we've been taught at A-Level), increasing pressure favours the side with the least amount of gaseous moles and, if there is the same amount of gaseous moles on either side, there's no change. On the OCR Chem A exam board we have had the odd 1 marker asking this. I'm not entirely sure if the (aq) moles affect this, but given the learned answer only mentions gaseous, I would have assumed (aq) moles aren't considered.
Hopefully someone more knowledgeable answers this!