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# M2 - kinematics question Watch

1. Could anyone show me how to do question 7 (c) from June 2012? Edexcel m2 exam
Attachment 550473
Even looking at the model answers on Physics and Maths tutor I can't get my head round the method.
2. (Original post by Music With Rocks)
Could anyone show me how to do question 7 (c) from June 2012? Edexcel m2 exam
Attachment 550473
Even looking at the model answers on Physics and Maths tutor I can't get my head round the method.
tan(theta) = 50/52.5.

Horizontal component of the velocity is constant. Vertical component of the velocity = u + at.

tan(theta) = horizontal component / vertical component = 50/52.5.
3. (Original post by Music With Rocks)
Could anyone show me how to do question 7 (c) from June 2012? Edexcel m2 exam
Attachment 550473
Even looking at the model answers on Physics and Maths tutor I can't get my head round the method.
Stone is "moving parallel to" means the "velocity is parallel to" OB.

As such the velocity will make the same angle to the horizontal as OB.

Tan of said angle = -52.5/50 = "vertical velocity" / "horizontal velocity"
where your vertical velocity is a function of t.

4. (Original post by ombtom)
tan(theta) = 50/52.5.

Horizontal component of the velocity is constant. Vertical component of the velocity = u + at.

tan(theta) = horizontal component / vertical component = 50/52.5.
(Original post by ghostwalker)
Stone is "moving parallel to" means the "velocity is parallel to" OB.

As such the velocity will make the same angle to the horizontal as OB.

Tan of said angle = -52.5/50 = "vertical velocity" / "horizontal velocity"
where your vertical velocity is a function of t.

Ah thank you both very much, I didn't even realise in the worked solutions that they were calculating the angle never mind why they were multiplying by 10.

I get it now, thank you that was a great help.

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