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    In an experiment, 9.0 moles of nitrogen and 27 moles of hydrogen were placed into a vessel of volume 10 dm3 and allowed to reach equilibrium. It was found that two thirds of the nitrogen and hydrogen were converted into ammonia. Calculate Kc for the reaction.
    N2(g) + 3H2(g) == 2NH3(g)
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    (Original post by shakeyboy)
    In an experiment, 9.0 moles of nitrogen and 27 moles of hydrogen were placed into a vessel of volume 10 dm3 and allowed to reach equilibrium. It was found that two thirds of the nitrogen and hydrogen were converted into ammonia. Calculate Kc for the reaction.
    N2(g) + 3H2(g) == 2NH3(g)
    Two thirds of 9.0 = ? and there is one third left unreacted
    Two thirds of 27.0 = ? and there is one third left unreacted

    Using the amount of nitrogen reacted how many moles of ammonia are formed.

    Now plug the values into the kc equation (equilibrium law)
 
 
 
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