The Student Room Group

Moles!!!

The formula for the production of ammonia in the haber process is as follows:
N2 + 3H2 ----> 2NH3

Molar mass
Nitrogen = 28
Hydrogen = 6
Ammonia = 34

How many moles are there in 2.8g of nitrogen?
number of moles = mass/molar mass =
2.8/28 = 0.1

How many moles of ammonia would form?
Ammonia has 2 moles so 0.1*2 = 0.2 moles would form

Work out the mass of ammonia formed.
0.2 * 34 = 6.8g

Have I answered everything correctly? Thank you in advance.
Original post by Wolfram Alpha
The formula for the production of ammonia in the haber process is as follows:
N2 + 3H2 ----> 2NH3

Molar mass
Nitrogen = 28
Hydrogen = 6
Ammonia = 34

How many moles are there in 2.8g of nitrogen?
number of moles = mass/molar mass =
2.8/28 = 0.1

How many moles of ammonia would form?
Ammonia has 2 moles so 0.1*2 = 0.2 moles would form

Work out the mass of ammonia formed.
0.2 * 34 = 6.8g

Have I answered everything correctly? Thank you in advance.


I'm pretty sure it's correct.


Posted from TSR Mobile
Original post by Firenze26
I'm pretty sure it's correct.


Posted from TSR Mobile


Thank you for your response.
check part (c)

28g of nitrogen makes 34g of ammonia. 1g of nitrogen forms 34/28 = 1.21g of ammonia.
So, 2.8g of nitrogen forms 2.8 * 1.21 = 3.388g = 3.4g of ammonia.
(edited 7 years ago)
Reply 4
Your answer is wrong - it should be 3.4g

1 mole of N2 gives 2 moles of NH3

1 mole of anything is its RAM (Mr) in g

so 1 mole of N2 is 28g and 1 mole of NH3 is 17g

so 2.8g of N2 gives 3.4 g of NH3
Original post by GDN
Your answer is wrong - it should be 3.4g

1 mole of N2 gives 2 moles of NH3

1 mole of anything is its RAM (Mr) in g

so 1 mole of N2 is 28g and 1 mole of NH3 is 17g

so 2.8g of N2 gives 3.4 g of NH3


Oops, he is correct. I guess I couldn't do simple maths lol ammonia is 34g :frown:.

Quick Reply

Latest