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    The formula for the production of ammonia in the haber process is as follows:
    N2 + 3H2 ----> 2NH3

    Molar mass
    Nitrogen = 28
    Hydrogen = 6
    Ammonia = 34

    How many moles are there in 2.8g of nitrogen?
    number of moles = mass/molar mass =
    2.8/28 = 0.1

    How many moles of ammonia would form?
    Ammonia has 2 moles so 0.1*2 = 0.2 moles would form

    Work out the mass of ammonia formed.
    0.2 * 34 = 6.8g

    Have I answered everything correctly? Thank you in advance.
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    (Original post by Wolfram Alpha)
    The formula for the production of ammonia in the haber process is as follows:
    N2 + 3H2 ----> 2NH3

    Molar mass
    Nitrogen = 28
    Hydrogen = 6
    Ammonia = 34

    How many moles are there in 2.8g of nitrogen?
    number of moles = mass/molar mass =
    2.8/28 = 0.1

    How many moles of ammonia would form?
    Ammonia has 2 moles so 0.1*2 = 0.2 moles would form

    Work out the mass of ammonia formed.
    0.2 * 34 = 6.8g

    Have I answered everything correctly? Thank you in advance.
    I'm pretty sure it's correct.


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    (Original post by Firenze26)
    I'm pretty sure it's correct.


    Posted from TSR Mobile
    Thank you for your response.
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    check part (c)

    28g of nitrogen makes 34g of ammonia. 1g of nitrogen forms 34/28 = 1.21g of ammonia.
    So, 2.8g of nitrogen forms 2.8 * 1.21 = 3.388g = 3.4g of ammonia.
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    Your answer is wrong - it should be 3.4g

    1 mole of N2 gives 2 moles of NH3

    1 mole of anything is its RAM (Mr) in g

    so 1 mole of N2 is 28g and 1 mole of NH3 is 17g

    so 2.8g of N2 gives 3.4 g of NH3
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    (Original post by GDN)
    Your answer is wrong - it should be 3.4g

    1 mole of N2 gives 2 moles of NH3

    1 mole of anything is its RAM (Mr) in g

    so 1 mole of N2 is 28g and 1 mole of NH3 is 17g

    so 2.8g of N2 gives 3.4 g of NH3
    Oops, he is correct. I guess I couldn't do simple maths lol ammonia is 34g .
 
 
 
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