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    Very stuck on this... have no clue :/
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    2H2O2(aq) 2H2O(I) + O2(g) this was the equation! 1dm3 under 2H2O2 and 20dm3 under O2
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    Yeah, we know that there's 20dm3 of O2, so we can calculate the moles of O2 because we know its volume and its molar volume at 25 degrees. n=volume/molar volume = n=20/24 = 0.83

    In the equation, H202 is 2moles while o2 is 1 mole so 2:1 ratio. So moles of h2o2 is 0.83 x 2 = 1.67moles

    The volume of h2o2 in the reaction is 1dm3 so c=n/v = 1.67/1 = 1.67mol dm3
 
 
 
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