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# D2 - transport problems question Watch

1. How did they get the shadowcost of twenty in the second iteration?
2. (Original post by LorryBalls)
How did they get the shadowcost of twenty in the second iteration?

Starting from S(X)=0

S(X)+ D(A) = 17, so D(A) = 17

S(Z)+ D(A) = 6, so S(Z) = -11

S(Z)+ D(C) = 9, so D(C) = 20
3. is this aqa?

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