D2 - transport problems question
How did they get the shadowcost of twenty in the second iteration?
Original post by LorryBalls
How did they get the shadowcost of twenty in the second iteration?
How did they get the shadowcost of twenty in the second iteration?
S refers to source shadow costs, D to destination shadow costs.
Starting from S(X)=0
S(X)+ D(A) = 17, so D(A) = 17
S(Z)+ D(A) = 6, so S(Z) = -11
S(Z)+ D(C) = 9, so D(C) = 20
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