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    Hi guys. Mind seems to have gone blank on me. Can anyone help me differentiate the following;

    T=16t - t[(1-t)^(-2)]

    Just a bit stuck on how to differentiate the (1-t) part. Any help welcome.


    Also. Apologies for not Latexing - can't seem to get it working.

    Thanks
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    (Original post by PrinceUpsb)
    Hi guys. Mind seems to have gone blank on me. Can anyone help me differentiate the following;

    T=16t - t[(1-t)^(-2)]

    Just a bit stuck on how to differentiate the (1-t) part. Any help welcome.


    Also. Apologies for not Latexing - can't seem to get it working.

    Thanks
    To differentiate the -t[(1-t)^(-2)], you first differentiate the t in the front, and then focus on the (1-t)^(-2). You need to use the chain rule. Do you know how to differentiate (1-t)^(-2)?
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    (Original post by PrinceUpsb)
    Hi guys. Mind seems to have gone blank on me. Can anyone help me differentiate the following;T=16t - t[(1-t)^(-2)]Just a bit stuck on how to differentiate the (1-t) part. Any help welcome.Also. Apologies for not Latexing - can't seem to get it working.Thanks
    Do you have the answer?


    I used quotient rule.
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    ignore that dT/dt, it should be the next line down.
    Also, it probably can be simplified further.
    After simplification: (1+t)/(1-t)3
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    Quotient or product rule will do.
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    (Original post by rayquaza17)
    To differentiate the -t[(1-t)^(-2)], you first differentiate the t in the front, and then focus on the (1-t)^(-2). You need to use the chain rule. Do you know how to differentiate (1-t)^(-2)?
    Yeah. (1-t)^(-2) will diff. to 2(1-t)^-3

    So my final answer I am getting is;

    dT/dt = 16 - 2(1-t)^-3

    can you confirm? I am just multiplying that part by the diff of 'the t in front'.

    Cheers
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    (Original post by PrinceUpsb)
    Yeah. (1-t)^(-2) will diff. to 2(1-t)^-3

    So my final answer I am getting is;

    dT/dt = 16 - 2(1-t)^-3

    can you confirm? I am just multiplying that part by the diff of 'the t in front'.

    Cheers
    Using quotient rule is better here.
    And no it is not true that (fg)'=f'g' as it seems you have done.
    If you want to use product rule you have to use (fg)'=gf'+fg'.
 
 
 
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