(GCSE) AQA Level 2 Further Maths Paper 1 (Non-Calc) 8360/1 20/06 Watch

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economy
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(GCSE) AQA Level 2 Further Maths Paper 1 (Non-Calc) 8360/1 20/06POSTED THIS ON WRONG FORUM BEFORE, OOPS!

1) Expand and differentiate 3x^2-20x
2) Multiply out matrices to equal the matrix given and solve a=3 b=-20
3) n=12
b) 3/5

4) (-5, 8)
b)root'10'

Graph question with turning point at y=0
--> coordinates of minimum were (3,0)
--> k = 9

(3-root'x' ) ^1/3 = -2
x = 121

sinx = root'11'/6
cosx = -5/6 because it was obtuse, and on a cosx graph, angles greater than 90 degrees are less than zero -> so it can't be positive (thanks yaystrawberries)

A lot of 'prove that' questions... you'll know if you've got those.
--> prove that triangle is isosceles (w=3n)
--> prove that the line segments are perpendicular (prove that -1/m)

Surds question √125 + √20 = √x + √80
x = 45

Factorise x^4-81
-->(x^2+9)(x^2-9) [1 mark]
-->(x^2+9)(x-3)(x+3) [1 mark]

Circle theorems question (cyclic quadrilateral)
--> x = 39

7) Write out the integer values, lose one mark for writing it as a range rather than integer values: 9, 10, 11

9) x^3-15x^2+75x-125

10) -80
11) Gradient AB = -5/2, Gradient BC= 2/5
12) h=3 k=-7
--> coordinates: (-3, -7)

14) 3a=3 a=1
b)(x+2)(x-7)(x-3)

15) 2 root'7' -4

I'm missing loads here, please comment and feel free to add or correct anything. How'd you think it went?
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yaystrawberries
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I only have a small thing to add, but for the sinx question, I'm pretty sure cosx = -5/6 because it was obtuse, and on a cosx graph, angles greater than 90 degrees are less than zero - so it can't be positive
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economy
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(Original post by yaystrawberries)
I only have a small thing to add, but for the sinx question, I'm pretty sure cosx = -5/6 because it was obtuse, and on a cosx graph, angles greater than 90 degrees are less than zero - so it can't be positive
Fab, cheers
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economy
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Fixed a few more things, this thing is practically complete now.
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LokiiR
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answers i got
1) 3x^2-20x (2)
2) a=3 b=-20 (3)
3)n=12 (2) b) 3/5 (1)
4)(-5, 8) b)root 10
5) x=39 degrees
6)m=8 p= -1
7) 9, 10, 11
8) x=121
9) x^3-15x^2+75x-125
10) -80
11) Gradient AB = -5/2, Gradient BC= 2/5 (3)
12) h=3 k=-7 b) (-3, -7) (1) c) -3+ or - root 7 (1)
13) x=45
14) 3a=3 a=1 (2?) b)(x+2)(x-7)(x-3)
15) 2root 7 -4
16) I got 5/6 but answer was -5/6 because it was obtuse (3)
17) k = 9 (5)
18) (x^2+9)(x-3)(x+3)
19)prove that the first part = 3, do it by doing sin45 = 1/root2, and 1/root2=x/3root2. Rearrange for 3. b)3 + 3 + 3 + 3root 3 is what you get for totals and factorise it to 3 (3+root 3) (4)
20) w = 3n because y use cosine rule and the answer = 1/3 rearrange it and then factorise it into two solutions but answer cant be negative so its n=w/3 and w=3n so two lengthsare equal and u get isosceles (4)
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