For the 4 marks I just said something like: The cathode is the pure copper and anode is the impure. I said how the direct current pulls electrons off of the anode, and that the copper atoms change to copper (Cu+) ions. They are attracted to the cathode... Blah blah blah.
Then for 6 marks:
First 6 marker:
-You get precise amount of acid needed to neutralise
-Means that universal indicator not needed, which would contaminate the solution
-Left with salt-water
-Heat solution gently
-Left with salt alone
-Flush salt with distilled water
-Leave to dry on filter paper
Second six mark:
-Substance A=Alkene/ unsaturated hydrocarbon
-Turns bromine water colourless
-Due to 'spare bonds' in the Alkene
-Substance B=Alcohol as it consists of 'COH'- to be precise- C(n)H(2n+1)OH
-Substance C=Carboxylic acid
-Substance D= Alkane
I could be wrong, but that's what I thought
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