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Edexcel Chemistry C3 Exam/Predictions

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What did everyone get for the 3 mark calculation questions?
I got 2.4 for the first one and 12.5 for the second one
Original post by chrlhyms
I would love them to ask me to draw an ester or carboxylic acid, easy marks which a lot of people couldn't get, and yeah i hope a good 4 mark on titrations comes up and other maths
You are soooo unbelievably lucky. Just, just that/
Original post by TSlayerr
Moles over vols (concentration). My teacher says this phase all the time. That's why I remember the formula :smile:


This helped me in the exam! Thanks haha!


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Original post by alan_jjj
What did everyone get for the 3 mark calculation questions?
I got 2.4 for the first one and 12.5 for the second one


I got the same! :smile:
Original post by SophFlorence
I got the same! :smile:


Hey, what did you get for the impure copper one, 4 marker on electrolysis? And the two 6 markers?
Original post by XherdanXhaka
Hey, what did you get for the impure copper one, 4 marker on electrolysis? And the two 6 markers?


For the 4 marks I just said something like: The cathode is the pure copper and anode is the impure. I said how the direct current pulls electrons off of the anode, and that the copper atoms change to copper (Cu+) ions. They are attracted to the cathode... Blah blah blah.

Then for 6 marks:

First 6 marker:
-You get precise amount of acid needed to neutralise
-Means that universal indicator not needed, which would contaminate the solution
-Left with salt-water
-Heat solution gently
-Left with salt alone
-Flush salt with distilled water
-Leave to dry on filter paper

Second six mark:
-Substance A=Alkene/ unsaturated hydrocarbon
-Turns bromine water colourless
-Due to 'spare bonds' in the Alkene
-Substance B=Alcohol as it consists of 'COH'- to be precise- C(n)H(2n+1)OH
-Substance C=Carboxylic acid
-Substance D= Alkane

I could be wrong, but that's what I thought :smile:


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Original post by SophFlorence
For the 4 marks I just said something like: The cathode is the pure copper and anode is the impure. I said how the direct current pulls electrons off of the anode, and that the copper atoms change to copper (Cu+) ions. They are attracted to the cathode... Blah blah blah.

Then for 6 marks:

First 6 marker:
-You get precise amount of acid needed to neutralise
-Means that universal indicator not needed, which would contaminate the solution
-Left with salt-water
-Heat solution gently
-Left with salt alone
-Flush salt with distilled water
-Leave to dry on filter paper

Second six mark:
-Substance A=Alkene/ unsaturated hydrocarbon
-Turns bromine water colourless
-Due to 'spare bonds' in the Alkene
-Substance B=Alcohol as it consists of 'COH'- to be precise- C(n)H(2n+1)OH
-Substance C=Carboxylic acid
-Substance D= Alkane

I could be wrong, but that's what I thought :smile:


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C is Ethanoic* acid but yeah, but the first 6 marker, it said it had to be done by titration? I just talked about titration then the Preparing Soluble Salts (1) in the book. I did (2) and (1).
Original post by XherdanXhaka
C is Ethanoic* acid but yeah, but the first 6 marker, it said it had to be done by titration? I just talked about titration then the Preparing Soluble Salts (1) in the book. I did (2) and (1).


Yes. I did write about the titration, but I didn't go in to too much depth on it. I more so talked about the actual preparing of the salt.


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Original post by SophFlorence
Yes. I did write about the titration, but I didn't go in to too much depth on it. I more so talked about the actual preparing of the salt.


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I just talked about both lol and hoped to get the marks. And the temperature linked with Haber Process, why not a higher temp used?
Original post by XherdanXhaka
I just talked about both lol and hoped to get the marks. And the temperature linked with Haber Process, why not a higher temp used?


It's because it would favour the endothermic reaction, meaning the percentage yield of ammonia would lessen.


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Original post by SophFlorence
It's because it would favour the endothermic reaction, meaning the percentage yield of ammonia would lessen.


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Think I talked about that too. So overall 48-51 A*?
Original post by XherdanXhaka
Think I talked about that too. So overall 48-51 A*?


That's good. Yeah, probably.


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Original post by SophFlorence
That's good. Yeah, probably.


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Lol that 1 marker that needed you to do the calculations? Like wth? I got 12.5 and 0.4 i think for one of them.
Original post by XherdanXhaka
Lol that 1 marker that needed you to do the calculations? Like wth? I got 12.5 and 0.4 i think for one of them.


So did I. I got 0.1 for the 1 marker.


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I don't recall getting 0.4- I got 2.4 for one of them. :smile:


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Original post by SophFlorence
I don't recall getting 0.4- I got 2.4 for one of them. :smile:


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yeah 2.4 lol, 0.1 x 24. You got an unofficial mark scheme?
Original post by XherdanXhaka
yeah 2.4 lol, 0.1 x 24. You got an unofficial mark scheme?


I haven't sorry:smile:


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Original post by SophFlorence
I haven't sorry:smile:


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Nvm, you look good btw :wink:
Reply 38
What did you write for the question about the dissolved solids in hard water- it was a question like how would you identify them without using soap. I put adding Sodium Hydroxide and then white precipitate for identifying calcium ions. Is that right?


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