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    An electrode cell is made from Zn2+/Zn and Cu2+/Cu.
    When the conc of Zn2+ is increase the equilibrium shifts forming more Zn. How does this make the electrode potencial more positive?
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    (Original post by Banana ice-cream)
    An electrode cell is made from Zn2+/Zn and Cu2+/Cu.
    When the conc of Zn2+ is increase the equilibrium shifts forming more Zn. How does this make the electrode potencial more positive?
    There are two equilibria in the half-cells:

    Cu2+ + 2e <==> Cu .................... + 0.34V
    Zn2+ + 2e <==> Zn .................... - 0.76V

    When the two half-cells are connected together the cell potential is 1.10V with the electrons attempting to flow from the Zn2+|Zn to the Cu2+|Cu around the external circuit.

    The spontaneous cell reaction is:
    Cu2+ + Zn --> Zn2+ + Cu

    The zinc half equation equilbrium is negative showing that the equilibrium tends to the left hand side, releasing electrons. If the Zn2+ is increased then this will push the equilibrium to the right hand side making the potential less negative (i.e. more positive)
 
 
 
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