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    Could someone please explain this equation VpIp= VsIs. When, where and how would you use this in the exam?
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    The voltage x current (power) is the same on the primary coil of a transformer to the secondary coil of the transformer.
    For example if you were told that the primary voltage (Vp) and current (Ip) into a transformer was 10volts and 5amps and the secondary voltage (Vs)was 25 volts you could work out the secondary current (Ip) is 2 ( 10x5/25=2)
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    what did people get for the area of the wall in section d?
 
 
 
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