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OCR Gateway Physics B - P4 P5 P6 - Unofficial Mark Scheme watch

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    Final science exam done! (I break up on Friday though )

    It was better than the P1 P2 P3 in my opinion but it was still difficult.

    How did you all find it?
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    (Original post by some-student)
    Final science exam done! (I break up on Friday though )

    It was better than the P1 P2 P3 in my opinion but it was still difficult.

    How did you all find it?
    Better than p1p2p3 definitely!!! The calculations were quite challenging but I think I managed to do quite well

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    I actually preferred the first paper! My physics teacher hadn't taught us the majority of the topics in the P5 section. Other than that, though, two out of the three six-markers were alright, and the majority of the questions- excluding the more challenging calculations- were relatively easy.
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    OCR Gateway Physics B
    P4 P5 P6 + Section D
    Unofficial Mark Scheme
    Wednesday 22 June 2016

    Module P4 - 25 marks
    1) Radiation treatment
    a) Explain why an alpha source cannot be used as a tracer [1]
    (too ionising and so) will not penetrate out of the skin (1)

    b)i) Explain why a radioactive source should not remain in the body for a long time [1]
    to not cause damage to healthy living cells (1)

    b)ii) What is the name given to how long a source stays radioactive? [1]
    half-life (1)

    c) Radiation may be used to treat brain cancer - explain why the head should be clamped [2]
    so that the gamma rays are focused on the tumour (1)
    to avoid damage to non-cancerous / healthy tissue / cells (1)

    2) Fuses and wiring [QWC 6]
    Marking points
    why only two wires are needed: it is double insulated and so the earth wire is not needed - even if the live wire becomes loose, the plastic cannot become live: maybe include purpose of live and neutral wires (to carry the voltage and complete the circuit respectively)

    why a fuse is needed: too large a current causes the fuse to melt, preventing flow of current, which prevents flex overheating and causing fire - and prevents further damage to appliance

    why a 13A fuse is used instead of 3A: operating current must be between 3A and 13A so that the fuse does not break under normal operation (this would happen for a 3A fuse), but also breaks if the current gets too high

    3) Static electricity
    a) Complete the sentence [1]
    he gains a positive charge because he loses electrons (1)

    b) Explain how anti-static sprays work [1]
    make surface of object conductive (1)

    c) Explain why the small strip attached to his car may be unreliable [1]
    not touching the ground / not made of a conductor/ easy to break off (1)

    d) Describe and risk and benefit of the petrol filler [2]
    risk: spark due to static charges which could cause an explosion (1)

    benefit: quick to use as flows out quickly / does not build up as much charge as it flows out quickly / reduces the amount of time during which the car and pump are in contact, reducing explosion risk (1)

    4) Nuclear radiation
    a) Write the letters in order [2]
    B, E, F, A

    four correct (2)
    two or three correct (1)
    otherwise (1)

    b) Explain the purpose of boron rods but explain why they need to be removed some times [2]
    absorb excess neutrons to stop reaction going out of control (1)

    (need to be removed so that) there are enough neutrons for the reaction to continue (1)

    5) Power, current, resistance and voltage
    a) Calculate the output voltage of the adapter [2]
    94V (2)
    incorrect answer with workings (1)

    b) In which country will the iron have the highest electrical power? They all use the same current. Explain your answer [1]
    Kenya, because it has the highest input voltage (1)

    c) In Japan, the iron is bad at ironing out creases. She attaches a variable resistor and then it become better at ironing out creases. Explain why [2]
    before, it had a low power as they all used the same current and it had the lowest input voltage (1)
    variable resistor can be used to decrease resistance and increase current, making the power greater (1)

    Module P5 - 25 marks
    6) Boat/speeds
    a) Difference between speed and velocity [1]
    speed only has a magnitude while velocity has a magnitude and direction (1)

    b) Which boat has the greatest resultant velocity? Why? [2]
    there is a debate over this question, so I have put on both answers

    boat X (1)
    explanation involving resultant velocity (1)

    or

    boat Y (1)
    explanation involving resultant velocity (1)

    c) Calculate the speed of the horse [2]
    example working (there may be other ways of doing it)
    s = ((u + v) / 2) × t

    t = 2s/(u + v) = 56 / 8 = 7 seconds

    7 seconds (2)
    incorrect answer with working (1)

    7) Cars
    a) Explain airbag release in terms of momentum [2]
    change in momentum when the gas particles collide with the airbag walls and change velocity (1)
    creating a force, creating a pressure (1)

    allow use of equations

    b) Calculate the speed of the car and if it was breaking the speed limit [3]
    6.5m/s (2)
    No (1) only if in relation to the answer for speed (no mark for 'No' without any other workings)

    otherwise

    working (1)

    8) Waves and interference
    a) Explain why the long wave radio waves have a long range [1]
    not sure about this

    any one of
    diffraction around large objects (1)
    and so can reach houses behind hills, for example (1)
    reflection from ionosphere (1)

    b) What are the properties of a wave needed for interference to occur? [2]
    same wavelength (1)
    coherent wave source (1)

    c) Partial destructive interference can occur. Suggest why this happens and the result it may have [2]
    not sure about this

    any one of
    waves partly in / out of phase (1)
    phase difference of (n + 1/4)λ, for example (1)

    and

    the wave may have a partial loss in quality (e.g. sound loss in some areas) (1)

    9) Dispersion/refraction
    a) Explain why the red light refracts away from the normal [2]
    passes over boundary between two media (glass and air) (1)
    wave speeds up (so bends away from the normal) (1)

    b) Explain why violet light refracts more [2]
    higher refractive index (1)
    wave speeds up more and so bends more (1)

    10) Projectile motion [QWC 6]
    Marking points
    path: the horizontal velocity is unaffected by gravity - therefore the horizontal velocity is constant; gravity causes the vertical velocity to increase (constant vertical acceleration) - but not increasing vertical acceleration

    calculation
    s = ut + 1/2at^2

    as the inital speed is 0, s = 1/2at^2

    therefore, t^2 = 2s/a

    therefore, t = (2s/a) = √(2/10) = 0.447213595 = 0.4s, or 0.45s

    Module P6 - 25 marks
    11) Truth table / logic gates / relay
    a) Complete the truth table [3]
    D column correct (1)
    E column correct (1)
    Output column correct (1)

    b) Explain the role of the relay [2]
    • a logic gate is a low power device that would be damaged if exposed directly to mains power / high voltages (1)
    • the relay isolates the low voltage in the sensing circuit from the high voltage (mains) (1)

    12) Power transmission
    a) Calculate the power loss in MW [2]
    100^2 * 20 = 2000000W = 2MW

    2MW (2)
    2000000W (1)

    b) Explain a risk and benefit of power transmission at high voltages [2]
    risk: electrocution / any other suitable risk (1)
    benefit: less power loss through heating of the cables (as lower current is needed) (1)

    13) Transformers - which two columns were wrong and why? [2]
    C, as wrong way round / step-up not step down / use of calculation (1)

    D, as wrong ratio / use of calculation (1)

    14) Motors and magnetic fields
    a) Draw the magnetic field around a solenoid [2]
    field lines at top and bottom (1)
    field lines at left and right sides (1)



    b) What does reversing the current do to the magnetic field? [1]
    (the magnetic field) reverses (1)

    c) How can a motor be made to spin faster? [1]
    any one of
    • increasing the size of the electric current (1)
    • increasing the number of turns on the coil (1)
    • increasing the strength of the magnetic field (1)

    15) Resistance graph
    a) Calculate the resistance [2]
    20Ω (2)
    incorrect answer with workings (substitution of x and y values into R=V/I) (1)

    b) What would happen to the gradient if the resistance value trebled? [2]
    gradient would increase (get steeper) (1)
    idea of gradient being (change in) y divided by (change in) x and comparison with R = V / I (1)

    16) Potential divider with LDR [QWC 6]
    Marking points
    - when it gets dark, LDR resistance increases, increasing its share of the input voltage (and so increases the output voltage)

    - when it gets very dark, LDR resistance increases so much that its share of the input voltage is nearly the entire input voltage, and so the output voltage can be said to be the input voltage (5V) - which is a logical 1 and so turns on the light

    - contrast of above point with lighter conditions in terms of: logical 1 and 0, and resistance

    Section D - 25 marks
    17) Smith family in the UK (500kWh per person per day) use 730000kWH per year
    a) Calculate the number of people in the Smith family [2]
    730000 / 365 = 2000kWh per day

    2000 / 500 = 4 people in the family

    4 people (2)
    incorrect answer with working (1)

    b) Belgium uses more per person per day than the UK. Suggest why Belgium may have a lower electrical consumption than the UK overall [1]
    lower population (1)

    18) U-values
    a) Calculate the energy lost per second with units: the U-value is 0.5W/m2°C, and the temperature difference was 12°C, and the area of the wall was 50m2[3]
    2 × 12 × 50 = 1200J/s

    either

    1200 (2) incorrect answer with workings (1)

    J/s (1) allow W

    or

    1.2 (2) incorrect answer with workings (1)

    kJ/s (1) allow kW

    b) Describe what would happen to energy transfer if the temperature difference increased [1]
    (it would) increase (1)

    c) Calculate the area of wall whose U-value was 0.5W/m2°C and the temperature difference along which was 12°C; 240J/s lost from the wall [3]
    Uvalue = power / (temperature * area)

    area = power / (temperature * Uvalue)

    area = 240 / (12 * 0.5) = 40m2

    40m2 (3)
    incorrect answer with all workings listed (2)
    incorrect answer with some workings listed (1)
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    (Original post by leopard923)
    Better than p1p2p3 definitely!!! The calculations were quite challenging but I think I managed to do quite well

    Posted from TSR Mobile
    I agree and I hope I have done well as I would like to take Physics A-level
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    (Original post by GCShElpme)
    I actually preferred the first paper! My physics teacher hadn't taught us the majority of the topics in the P5 section. Other than that, though, two out of the three six-markers were alright, and the majority of the questions- excluding the more challenging calculations- were relatively easy.
    Well hopefully you did well
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    Thank you so much for making these!
    For section D I got 4 people
    1200J/s
    40m^2

    Is this right?

    Also I got 0.45 s for the P5 6 marker?

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    (Original post by mxskaan)
    Thank you so much for making these!
    For section D I got 4 people
    1200J/s
    240m^2

    Is this right?

    Also I got 0.45 s for the P5 6 marker?

    Posted from TSR Mobile
    I got all of those apart from 40m^2 for the section D.

    What I did was:

    U-value = power / (temp. * area)

    area = power / temp. * U - value

    area = 240 / 12 * 0.5 = 40 m^2
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    (Original post by some-student)
    I agree and I hope I have done well as I would like to take Physics A-level
    Same here!

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    (Original post by some-student)
    I got all of those apart from 40m^2 for the section D.

    What I did was:

    U-value = power / (temp. * area)

    area = power / temp. * U - value

    area = 240 / 12 * 0.5 = 40 m^2
    I got 40 too

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    (Original post by leopard923)
    I got 40 too

    Posted from TSR Mobile
    I'm not too sure how, but I think I got 20? Do you think that I'd be able to pick up a mark or two despite my wrong answer?
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    (Original post by some-student)
    I got all of those apart from 40m^2 for the section D.

    What I did was:

    U-value = power / (temp. * area)

    area = power / temp. * U - value

    area = 240 / 12 * 0.5 = 40 m^2
    I GOT 40 TOO I MADE A TYPO
    Ahhhh so glad
    Btw I got 7s for the acceleration. I also got 6.5m/s for momentum and answer no.
    I got 20 ohms for resistance and 94W for power.

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    (Original post by leopard923)
    I got 40 too

    Posted from TSR Mobile
    Calculations of the top of my head

    p5

    Resultant velocity would be 6 so Y is greatest

    Would take horse 7 seconds

    Car wasn't over speed limmit, it was 6.5 m/s

    P5 6 maker: 0.45
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    (Original post by leopard923)
    Same here!

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    (Original post by leopard923)
    I got 40 too

    Posted from TSR Mobile
    Great

    (Original post by GCShElpme)
    I'm not too sure how, but I think I got 20? Do you think that I'd be able to pick up a mark or two despite my wrong answer?
    You can probably get marks for working because it was worth 3 marks

    (Original post by mxskaan)
    I GOT 40 TOO I MADE A TYPO
    Ahhhh so glad
    Btw I got 7s for the acceleration. I also got 6.5m/s for momentum and answer no.

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    Those are right as well
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    For the P6 six marker, I said that a high resistance across the resistor (not the LDR, then one placed before it) means a low voltage so a high voltage across the LDR switching the security unit on. Is this correct?
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    Also, was it NAND or NOR?
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    (Original post by Arian Nazifi)
    Calculations of the top of my head

    p5

    Resultant velocity would be 6 so Y is greatest

    Would take horse 7 seconds

    Car wasn't over speed limmit, it was 6.5 m/s

    P5 6 maker: 0.45
    Yeah, I agree with all of these.
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    (Original post by Wolfram Alpha)
    Also, was it NAND or NOR?
    NOR I think

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    (Original post by Wolfram Alpha)
    For the P6 six marker, I said that a high resistance across the resistor (not the LDR, then one placed before it) means a low voltage so a high voltage across the LDR switching the security unit on. Is this correct?
    I think it was that when it gets dark the LDR gets a higher resistance and so has a higher share of the output voltage and when it gets really dark the LDR will have such a high resistance that the output voltage is basically the input voltage which is 5V - a logical 1 and so turns on the light

    (Original post by Wolfram Alpha)
    Also, was it NAND or NOR?
    It was NOR
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    (Original post by Wolfram Alpha)
    Also, was it NAND or NOR?
    I thought it was an OR gate.
 
 
 
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