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# what do I do when I get a negative ln term + a negative ln term? watch

1. If I have -ln(2x-6) - 2ln(x-6) do I combine the terms to get -ln((2x-6)/(x-6)^2) or have I made a mistake somewhere?
2. (Original post by Luketheace)
If I have -ln(2x-6) - 2ln(x-6) do I combine the terms to get -ln((2x-6)/(x-6)^2) or have I made a mistake somewhere?
Your answer is wrong. If you take out the minus it should become clearer:

Now join together the logs inside the bracket.
3. Thanks for the response, I've seen the mistake now.
I'm trying to integrate 1/((2x-6)(x-6)) using partial fractions and it just seems impossible at the moment
4. (Original post by Luketheace)
Thanks for the response, I've seen the mistake now.
I'm trying to integrate 1/((2x-6)(x-6)) using partial fractions and it just seems impossible at the moment
If you're still having problems then please post your working up to the point you got stuck.

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Updated: June 22, 2016
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