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    Here is the model answer for C34 June 2016 paper.
    https://drive.google.com/open?id=0Bz...TQ4MGNhS2pibzA
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    I think that most of the questions were straightforward although the paper was a little bit lengthy
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    (Original post by koli248)
    Here is the model answer for C34 June 2016 paper.
    https://drive.google.com/open?id=0Bz...TQ4MGNhS2pibzA
    Hi, thank you very much for these.

    I do feel your #2 is wrong, though - dy/dx at P is \frac{1}{\pi}, so shouldn't there be a - sign?

    Also, for 10(b) they asked for exam form.

    Do you think I'd lose a mark for giving my answer for the last one as 11.63 without the units?
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    You're welcome
    yes you're right I've corrected it

    No I think you won't lose a mark.
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    Just did the paper and realised your question 13C is wrong.
    you went from ln(h)+10ln(30-h)=-t +ln(k) to 10ln(h^2(30-h)) = -t +ln(k), you accidentally made it h^2 inside the ln
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    I got t=9.40(2dp)
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    (Original post by Nerrad)
    I got t=9.40(2dp)
    Pretty sure his answer is correct - I got the same one integrating with limits
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    (Original post by Nerrad)
    Just did the paper and realised your question 13C is wrong.
    you went from ln(h)+10ln(30-h)=-t +ln(k) to 10ln(h^2(30-h)) = -t +ln(k), you accidentally made it h^2 inside the ln
    It is 20ln(h) not ln(h). Thats why it became 10ln(h^2).
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    (Original post by Ayman!)
    Pretty sure his answer is correct - I got the same one integrating with limits
    Oh my bad! Didn't realise 20 had turned into 10 to make it h^2
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    (Original post by koli248)
    It is 20ln(h) not ln(h). Thats why it became 10ln(h^2).
    My bad, thanks for correcting
 
 
 
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