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    Could somebody here please inform me how 2/(2^(8) is the same as 1/(2^(7)?

    I can't seem to figure out any logical answer explaining how halving the numerator changers the exponent on the denominator by -1?

    I'm sure i'm being an idiot here but I can't figure it out.
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    (Original post by Squire1998)
    Could somebody here please inform me how 2/(2^(8) is the same as 1/(2^(7)?

    I can't seem to figure out any logical answer explaining how halving the numerator changers the exponent on the denominator by -1?

    I'm sure i'm being an idiot here but I can't figure it out.
    \frac{x^a}{x^b} = ....?

    The opposite is  x^a \times x^b = x^{a+b} if that helps. (or think about what it means when b is negative)
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    2/2^8 = 2/2x2x2x2x2x2x2x2

    The 2 in the numerator cancels one of the 2's in the denominator hence:

    1/2^7 = 1/2x2x2x2x2x2x2
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    (Original post by tjena)
    2/2^8 = 2/2x2x2x2x2x2x2x2

    The 2 in the numerator cancels one of the 2's in the denominator hence:

    1/2^7 = 1/2x2x2x2x2x2x2
    Ah, so I was being an idiot. Thanks! that's cleared it up.
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    (Original post by Squire1998)
    Ah, so I was being an idiot. Thanks! that's cleared it up.
    No worries. Good luck
 
 
 
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