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# Maths help Watch

1. The question is asking me to circle the equation with roots 4 and -8 and the options are: 4x(x-8)=0, (x-4)(x+8)=0, x^2 -32 = 0 and (x+4)(x-8)=0. The answer is not what I'm interested in but more so how to go about answering similar questions like these
2. A polynomial with roots has equation .
Since when you plug in one of the roots for x it will be equal to 0.
3. Ok so first of all solve each of the x values when the equation is equal to 0

For example on the first one, 4x=0 and x-8=0

what are the roots of this first equations? (ie what are the values of x)

repeat this method for the other three equations
4. (Original post by Botcampers)
The question is asking me to circle the equation with roots 4 and -8 and the options are: 4x(x-8)=0, (x-4)(x+8)=0, x^2 -32 = 0 and (x+4)(x-8)=0. The answer is not what I'm interested in but more so how to go about answering similar questions like these
isn't this a question in the new gcse maths paper(aqa)
5. (Original post by theBranicAc)
isn't this a question in the new gcse maths paper(aqa)
Not sure. My teacher gave it to me so I could revise
6. (Original post by Katiee224)
Ok so first of all solve each of the x values when the equation is equal to 0

For example on the first one, 4x=0 and x-8=0

what are the roots of this first equations? (ie what are the values of x)

repeat this method for the other three equations
Oh! That makes sense. I was baffled by the word root but now it makes sense. Just look for the values of X. Thank you
7. (Original post by Botcampers)
Oh! That makes sense. I was baffled by the word root but now it makes sense. Just look for the values of X. Thank you
The values of x are when y=0. If you plotted the graph of each of these equations you would see this is where the graph crosses the x-axis.

I recommend you draw out the graphs to see visually where the routes are once you've found them.
8. Just to elaborate, this is why we set equations to 0 and factorise, if a polynomial has roots, 2, 3 , 1 and -1 then its equation would be .

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Updated: June 30, 2016
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