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# C3 functions watch

1. http://www.examsolutions.net/a-level...y/paper.php#Q6

6c what am i supposed to do?
i mean i can find the equation of both lines but how can that help me?
2. gg(2)=g(g(2)). g(2)=0, so find g(0).
3. (Original post by bigdonger)
how do i know this? just a fact?
If you read the graph of g(x), 2 on the x-axis is at 0 on the y, hence g(2)=0.
4. (Original post by bigdonger)
how do i know this? just a fact?
From the graph, it passes through (2,0).
5. (Original post by bigdonger)
http://www.examsolutions.net/a-level...y/paper.php#Q6

6c what am i supposed to do?
i mean i can find the equation of both lines but how can that help me?
As mentioned above, gg(2) = g(g(2)) and you should work from inside out, so g(2) first, which from the graph is 0 (when x is 2, y is 0). Then you do g(0) which is -6 (when x is 0, y is -6)
6. (Original post by an_atheist)
If you read the graph of g(x), 2 on the x-axis is at 0 on the y, hence g(2)=0.
(Original post by HapaxOromenon3)
From the graph, it passes through (2,0).
ah thanks
7. (Original post by asinghj)
As mentioned above, gg(2) = g(g(2)) and you should work from inside out, so g(2) first, which from the graph is 0 (when x is 2, y is 0). Then you do g(0) which is -6 (when x is 0, y is -6)
What's the purpose of me doing this?
8. (Original post by bigdonger)
What's the purpose of me doing this?
gg(2)=g(g(2). g(2)=0, therefore by substitution, gg(2)=g(0)=-6
9. (Original post by an_atheist)
gg(2)=g(g(2). g(2)=0, therefore by substitution, gg(2)=g(0)=-6
ah i see thanks
10. (Original post by bigdonger)
What's the purpose of me doing this?
Because they want gg(2) which is g(g(2)) and focusing on g of 2 you get 0 and so putting 0 instead of g(2) on the g(g(2)) you get g(0) which is -6
11. (Original post by asinghj)
Because they want gg(2) which is g(g(2)) and focusing on g of 2 you get 0 and so putting 0 instead of g(2) on the g(g(2)) you get g(0) which Is 6
thanks

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