Hey there! Sign in to join this conversationNew here? Join for free
Turn on thread page Beta
    • Thread Starter
    Offline

    2
    ReputationRep:
    http://www.examsolutions.net/a-level...y/paper.php#Q6

    6c what am i supposed to do?
    i mean i can find the equation of both lines but how can that help me?
    • Community Assistant
    Offline

    15
    ReputationRep:
    Community Assistant
    gg(2)=g(g(2)). g(2)=0, so find g(0).
    • Community Assistant
    Offline

    15
    ReputationRep:
    Community Assistant
    (Original post by bigdonger)
    how do i know this? just a fact?
    If you read the graph of g(x), 2 on the x-axis is at 0 on the y, hence g(2)=0.
    Offline

    3
    ReputationRep:
    (Original post by bigdonger)
    how do i know this? just a fact?
    From the graph, it passes through (2,0).
    Offline

    16
    ReputationRep:
    (Original post by bigdonger)
    http://www.examsolutions.net/a-level...y/paper.php#Q6

    6c what am i supposed to do?
    i mean i can find the equation of both lines but how can that help me?
    As mentioned above, gg(2) = g(g(2)) and you should work from inside out, so g(2) first, which from the graph is 0 (when x is 2, y is 0). Then you do g(0) which is -6 (when x is 0, y is -6)
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by an_atheist)
    If you read the graph of g(x), 2 on the x-axis is at 0 on the y, hence g(2)=0.
    (Original post by HapaxOromenon3)
    From the graph, it passes through (2,0).
    ah thanks
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by asinghj)
    As mentioned above, gg(2) = g(g(2)) and you should work from inside out, so g(2) first, which from the graph is 0 (when x is 2, y is 0). Then you do g(0) which is -6 (when x is 0, y is -6)
    What's the purpose of me doing this?
    • Community Assistant
    Offline

    15
    ReputationRep:
    Community Assistant
    (Original post by bigdonger)
    What's the purpose of me doing this?
    gg(2)=g(g(2). g(2)=0, therefore by substitution, gg(2)=g(0)=-6
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by an_atheist)
    gg(2)=g(g(2). g(2)=0, therefore by substitution, gg(2)=g(0)=-6
    ah i see thanks
    Offline

    16
    ReputationRep:
    (Original post by bigdonger)
    What's the purpose of me doing this?
    Because they want gg(2) which is g(g(2)) and focusing on g of 2 you get 0 and so putting 0 instead of g(2) on the g(g(2)) you get g(0) which is -6
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by asinghj)
    Because they want gg(2) which is g(g(2)) and focusing on g of 2 you get 0 and so putting 0 instead of g(2) on the g(g(2)) you get g(0) which Is 6
    thanks
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: July 16, 2016
Poll
“Yanny” or “Laurel”
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.