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# How is -4 divided by -4 = -8 watch

1. I don't understand how -8 is the answer........
2. (Original post by Jack_Tomlin)
I don't understand how -8 is the answer........
Its not.
3. It's not...?
5. (Original post by Jack_Tomlin)
I don't understand how -8 is the answer........
1 xDD
6. Its not, is it?

-4 - 4 = -8

-4 / -4 = 1

No?
7. -4/-4 Firstly two negatives cancel out hence its 4/4 which is 1 therefore by mathematical induction it does not equal -8....
9. (Original post by meemily)
Its not, is it?

-4 - 4 = -8

-4 / -4 = 1

No?
That's what I got on my calculator lol
10. (Original post by NoahMal)
-4/-4 Firstly two negatives cancel out hence its 4/4 which is 1 therefore by mathematical induction it does not equal -8....
Erm no...
11. (Original post by Jack_Tomlin)
That's what I got on my calculator lol
Sounds broken

You should probably check that its on the right settings (if you used brackets)
12. I just used my scientific calculator instead of my phone and got 1
13. Ok so how would I get -8x on its own? This is from a linear equation
14. 0^0 = 1^0 = 1. Therefore 0 = 1.
Hence -4/-4 = -4(1)/-4 = -4(0)/-4 = 0/-4 = 0 = 8*0 = 8*(-0) = 8*(-1) = -8
15. (Original post by 13 1 20 8 42)
0^0 = 1^0 = 1. Therefore 0 = 1.
Hence -4/-4 = -4(1)/-4 = -4(0)/-4 = 0/-4 = 0 = 8*0 = 8*(-0) = 8*(-1) = -8
QED
16. (Original post by Jack_Tomlin)
I just used my scientific calculator instead of my phone and got 1
17. So can I use these rules when dividing as well as multiplying?

- - = +
++ = +
- + = -
+ - = -
18. (Original post by 13 1 20 8 42)
0^0 = 1^0 = 1. Therefore 0 = 1.
Hence -4/-4 = -4(1)/-4 = -4(0)/-4 = 0/-4 = 0 = 8*0 = 8*(-0) = 8*(-1) = -8
is it? numberphile did a vid on that and said that it could be 0 or 1 or used to argue the situation or number which you need(which is generally 1)

interesting though
19. you don't need a calculator to work something out that you learnt in year 6/7...
20. (Original post by thegreatwhale)
is it? numberphile did a vid on that and said that it could be 0 or 1 or used to argue the situation or number which you need(which is generally 1)

interesting though
I thought it was undefined until this year and I'm a maths student lel. As far as I know it is generally accepted to be 1 but I can't recall why even though I have looked into it before.

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