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    2 circles, each of radius r, overlap each other and the centre of one circle is the circumference of the other circle. Show that the area of overlap is r^2/4(4pi-3root3).

    How would I go about this? I have no idea where to start lol


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    (Original post by Mr Pussyfoot)
    2 circles, each of radius r, overlap each other and the centre of one circle is the circumference of the other circle. Show that the area of overlap is r^2/4(4pi-3root3).

    How would I go about this? I have no idea where to start lol


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    Hint : try to form sectors of radius r in the overlapping region.

    The denominator of the answer is 6 not 4 so the answer is

    \displaystyle \frac{r^2}{6}\left(4\pi-3\sqrt{3}\right)
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    (Original post by MartyO)
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    Heya! I see that you've been answering a few threads as of late, just thought that I'd let you know that here on TSR, we prefer to guide users and refrain from posting full solutions to queries, instead, that is left as a last ditch resort. Indeed, given that notnek posted a hint, it comes off as a bit rude for you to post a full solution. Thanks for reading and understanding! :-)
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    (Original post by notnek)
    Hint : try to form sectors of radius r in the overlapping region.

    The denominator of the answer is 6 not 4 so the answer is

    \displaystyle \frac{r^2}{6}\left(4\pi-3\sqrt{3}\right)
    Thanks! I had trouble visualising it at first but the hint really helped. And yes it is r^2/6 (my mistake lol)


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    (Original post by MartyO)
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    I think this method is a little too advanced for someone at my level!😂 But never would have imagined the problem could be approached in this way


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