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    Hi I really don't understand how you would work these questions out, thanks for any help. (It's questions 2 and 4 that I don't understand)
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    (Original post by Meggy moo 1)
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    Hi I really don't understand how you would work these questions out, thanks for any help. (It's questions 2 and 4 that I don't understand)
    Are you supposed to be using the Newton-Raphson method? If so you just use the iterative formula  \displaystyle x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)} .
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    (Original post by B_9710)
    Are you supposed to be using the Newton-Raphson method? If so you just use the iterative formula  \displaystyle x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)} .
    Sorry I don't know what that is as I've never been taught it
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    You only have to try the numbers 0,1,2,3,4,5 because it says integer, if you're really stuck, try them all until the equation equals zero
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    just look up iterative formula on exam solutions, I'm pretty sure in question 2 your trying to find N,N+1, so for example say N=1, Then the interval is 1to 2.
    So input x=1 and x=2 into the equation and one answer should be negative and one positive, which indicates the graph has gone through the x axis between 1 & 2 hence the root {y=0 or f(x)=0} falls between 1&2 as there is a change of sign (+ to -).
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    (Original post by Donkey******)
    You only have to try the numbers 0,1,2,3,4,5 because it says integer, if you're really stuck, try them all until the equation equals zero
    I did that and I managed to complete the exercise correctly now, thank you!


    (Original post by philo-jitsu)
    just look up iterative formula on exam solutions, I'm pretty sure in question 2 your trying to find N,N+1, so for example say N=1, Then the interval is 1to 2.
    So input x=1 and x=2 into the equation and one answer should be negative and one positive, which indicates the graph has gone through the x axis between 1 & 2 hence the root {y=0 or f(x)=0} falls between 1&2 as there is a change of sign (+ to -).
    That made a lot of sense when I tried the work again, thanks
 
 
 
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