Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    7
    ReputationRep:
    Question 3 Jan 2005.

    http://files.physicsandmathstutor.co...%20Edexcel.pdf

    For a) I got

    S = ?
    U = 0
    V = 9
    A = ?
    T = 20

    but I'm unsure with how correct this is
    Offline

    7
    ReputationRep:
    For a)

    used areas as the distance is the area under the speed-time graph as Speed=Distance/Time so Distance=Speed*Time so do the area of the right angle triangle plus the area of the square upto that time. Make sure you take length of square as 16 and not 20!! Look at the diagram carefully
    Offline

    7
    ReputationRep:
    SUVAT comes into play later for part B) and C)
    • Thread Starter
    Offline

    7
    ReputationRep:
    Oh god hahahaha, can't believe how stupid that mistake was. Thanks!
    • Thread Starter
    Offline

    7
    ReputationRep:
    For part b) the distance between 20s - 25s would be 38m right? Because 200m - 162m = 38m
    and the area accounts for distance but if you work out the area for the trapezium it would be (4+9 /2 ) * 5 which is 32.5 ..
    Offline

    7
    ReputationRep:
    Yes for a) it's 162m and yes you could do that for b) but I would try to calculate an area=200 so you know that the triangle and square make 162m,then make an equation with u for the last trapezium and equate it to 200m
    Offline

    7
    ReputationRep:
    Last trapezium equation to + to 162m and =200m

    And hence solve for u
    Spoiler:
    Show
    Trapezium equation =1/2(parallel a+ longer longer parallel side b)*hieght =1/2(9+u)*5
    • Community Assistant
    • Welcome Squad
    Offline

    20
    ReputationRep:
    Community Assistant
    Welcome Squad
    (Original post by Mina_)
    Question 3 Jan 2005.

    http://files.physicsandmathstutor.co...%20Edexcel.pdf

    For a) I got

    S = ?
    U = 0
    V = 9
    A = ?
    T = 20

    but I'm unsure with how correct this is
    (a) It's asking for distance covered which would equate to the area. If you consider the first 20 seconds you can split it into a triangle with length of time 4 seconds and the a rectangle with length of time 16 seconds. Add these areas together.

    (b) The last part of the graph is a trapezium. Area of that trapezium and the answer from part (a) should make up 200 in terms of u. Solve for u.

    (c) Deceleration would be the gradient of the line between 20 and 25 seconds.
    • Community Assistant
    • Political Ambassador
    Offline

    22
    ReputationRep:
    Community Assistant
    Political Ambassador
    (Original post by Mina_)
    Question 3 Jan 2005.
    http://files.physicsandmathstutor.co...%20Edexcel.pdf
    For a) I got
    S = ?
    U = 0
    V = 9
    A = ?
    T = 20
    but I'm unsure with how correct this is
    In a velocity-time graph (or speed-time graph) distance is represented by the area under the line.

    What I'm wondering is why this question now? Are you learning M1 over the summer?
    • Thread Starter
    Offline

    7
    ReputationRep:
    (Original post by 04MR17)
    In a velocity-time graph (or speed-time graph) distance is represented by the area under the line.

    What I'm wondering is why this question now? Are you learning M1 over the summer?
    We've finished kinematics right before summer term started so right now I'm consolidating
    • Community Assistant
    • Political Ambassador
    Offline

    22
    ReputationRep:
    Community Assistant
    Political Ambassador
    (Original post by Mina_)
    We've finished kinematics right before summer term started so right now I'm consolidating
    Nice. I'm learning it over the summer. Purely because I don't want to be struggling with it when the physics people are whinging about how easy it is and how they don't understand how it can be hard. I've done vectors and am now halfway through kinematics (watching examsolutions videos).
 
 
 
Poll
Do you agree with the PM's proposal to cut tuition fees for some courses?
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.